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2 years ago

Solve kx + 8 = 4 for x.

Mathematics

1 answer:

AnnyKZ [126]2 years ago

4 0

Answer:

A.4

hope it is ❤❤❤❤

THANK YOU.

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PLS HELP

NeTakaya

I don’t know o had this question two and couldn’t find the answer

8 0

2 years ago

Read 2 more answers

Simplify the expression please

Reika [66]

$\bf -2(3+2i)+2(4-5i)\implies 
\\\\\\
-6+8-10i-4i\implies \boxed{2-14i}$

3 0

3 years ago

Which of the following expressions is modeled on the number line?

Anton [14]

Answer is D. last one
2 * 3 = 6
On the number line, 0 to 3, it's 3 units
then 3 to 6, there's another 3 units
so 2 x 3(units) = 6

7 0

2 years ago

Which expression of signed decimal numbers has a positive quotient?

melomori [17]

Answer:

it would be -1.7 / -10.06 because if you divide 2 negative numbers than you get a positive number and if you divide a negative and a positive number than it would be negative

Hope this helps you ❤️

Step-by-step explanation:

7 0

3 years ago

PLSS HELP ILL GIVE YOU BRAINLIEST!!

uysha [10]

Answer:

Step-by-step explanation:

Q1)

Use Phythogoras theorem:

$(AC)^2=(BC)^2+(AB)^2\\BC^2=AC^2-AB^2\\BC^2=6^2-4^2\\BC^2=36-16\\BC^2=20\\\\Apply\ square\ on\ both\ sides\\\\\sqrt{BC^2}=\sqrt{20} \\BC=\sqrt{20} \\BC=\sqrt{10(2)} \\BC=\sqrt{5(2)(2)} \\BC=2\sqrt{5}$

Q2)

Apply phythogoras theorem:

$CD^2=CE^2+DE^2\\CD^2=7^2+9^2\\CD^2=49+81\\CD^2=130\\\\Apply\ square\ root\ on\ both\ sides\\\\\\sqrt{CD^2} = \sqrt{130} \\\\CD=\sqrt{130} \\\\CD=11.4$

Q3)

Apply phythogoras theorem again:

$BC^2=BD^2+CD^2\\BC^2=7^2+13^2\\BC^2=49+169\\BC^2=218\\\\Apply\ square\ root\ on\ both\ sides\\\\\\sqrt{BC^2} =\sqrt{218} \\\\BC=\sqrt{218} \\\\BC=14.76$

I have an attached an image for Question 2 for better understanding the length of DE in question equals 15 - 6 = 9

4 0

2 years ago