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3 years ago

Find the 4th term of the expansion of (a - sqrt(2)) ^ 8

Mathematics

2 answers:

charle [14.2K]3 years ago

6 0

Answer:

Applying the binomial theorem

$(x+a)^{n}=\sum _{k=0}^{n}{n \choose k}x^{n-k}a^{k}$

Here we have x = - $\sqrt{2}$ , n = 8,

=> 4th term (k = 3) would be:

${8 \choose 3}x^{8-3}a^{3}} = {8 \choose 3}(-\sqrt{2})^{5}a^{3}} = -224a^{3}\sqrt{2}$

Hope this helps!

vredina [299]3 years ago

3 0

Answer:

Step-by-step explanation:

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Julio bought 12 bulbs of jumbo garlic for $11.88. How many bulbs of jumbo garlic can Anjali buy if she has $3.96?

Molodets [167]

Answer:

Anjali can buy 4 bulbs of jumbo garlic if she has $3.96.

Step-by-step explanation:

To calculate how many bulbs of jumbo garlic Anjali can buy with $3.96, we must first calculate the unit rate of the jumbo garlic. Julio buying 12 bulbs of jumbo garlic for $11.88 can be represented as:

$\frac{11.88}{12}$

Divide the fraction by $\frac{12}{12}$ to calculate the unit rate:

$\frac{.99cents}{1bulb}$

So if each bulb of garlic costs $0.99, which we can think of as being $1.00 at the moment, we could figure that Anjali's $3.96 would be closer to $4 than it is to $3, so let's multiply the unit rate by $\frac{4}{4}$ :

$\frac{.99}{1}$ × $\frac{4}{4}=$

$\frac{3.96}{4}$

Therefore, Anjali can buy 4 bulbs of jumbo garlic if she has $3.96.

Check your work by dividing $\frac{3.96}{4}$ by $\frac{4}{4}$ to see if you will get your initial unit rate:

$\frac{3.96}{4}$ ÷ $\frac{4}{4} =$

$\frac{0.99}{1}$

Therefore, our solution is correct!

7 0

3 years ago

Read 2 more answers

Please help!!! Is this correct????

ahrayia [7]

Answer:

yes

Step-by-step explanation:

Weight appears to be the independent variable, so will be graphed on the horizontal axis. Cost is the dependent variable, so will be graphed on the vertical axis.

5 0

3 years ago

What is the quotient of 905.8 and 0.2?

alexdok [17]

Answer: 4529

Step-by-step explanation:

Hope it helps Have a good Day

Just divide it

6 0

3 years ago

What's the equation:

ElenaW [278]

Using shifting concepts, it is found that the function g is:

$g(x) = -9x^2 - 198x - 1085$

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The parent function is $f(x) = x^2$ .

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Horizontally stretching a function by a factor of b is the finding $f(\frac{x}{b})$ .
Thus, horizontally stretching by a factor of 1/3, we have: