Can someone please help me on this

Suppose that nine is a factor of a number which statement has to be true

Since 9 is a factor of an unknown number, that means that that number has to be a multiple of 9. If 9 is the factor of something then that something HAS to be a multiple of 9.

6 0

3 years ago

The manufacturer of an energy drink spends $1.20 to make each drink and sells them for two dollars the manufacturer also has fix

dimulka [17.4K]

Let X be the number of energy drinks sold.

The manufacturer of an energy drink spends $1.20 to make each drink and sells them for two dollars the manufacturer also has fixed cost each month of $8000.

The manufacturing cost for X energy drinks is

$1.20x$

Fixed cost is $8000.

Therefore, cost function is

$C(x)=1.20x+8000$

Selling price of each drink is $2.

Therefore, the revenue function is

$R(x)=2x$

Hence, the revenue function is

$R(x)=2x$

6 0

1 year ago

Solve.

baherus [9]

The correct answer is: [C]: " 5 " .
__________________________________________________________
→ " a = 5 " .
__________________________________________________________
Explanation:
__________________________________________________________

Given: " a + 1 <span>− 2 = 4 " ; Solve for "a" ;

4 + 2 = 6 ;

6 </span>− 1 = 5 ; → a = 5 ;

To check our work:

5 + 1 − 2 = ? 4 ?? ;

5 + 1 = 6 ;

6 − 2 = 4. Yes!

So the answer is: [C]: " 5 ".
_________________________________________________________
→ " a = 5 " .
_________________________________________________________

4 0

3 years ago

Grain is falling from a chute onto the ground, forming a conical pile whose diameter is always three times its height. how high

bezimeni [28]

Given that grain is falling from a chute onto the ground, forming a conical pile whose diameter is always three times its height.

So if D is the diameter and h is the height of the conical pile then we can write:

D=3h

We know that diameter = 2r, where r is the radius

2r=3h

$r=\frac{3h}{2}$

Volume of conical pile is given by formula

$V=\frac{1}{3}\pi r^2h$

Given that volume is 1110 cubic feet.

Now plug the values of Volume and r into equation of volume

$1110=\frac{1}{3}\pi (\frac{3h}{2})^2h$

$1110=\frac{1}{3}\pi\cdot\frac{9h^2}{4}\cdot h$

$1110=\pi\cdot\frac{3h^3}{4}$

$1110\cdot\frac{4}{3\pi}=h^3$

$471.098631552=h^3$

take cube root of both sides

7.78103342467=h

Hence height is approx 7.78 feet.

7 0

3 years ago

On a morning of a day when the sun will pass directly overhead, the shadow of a 60-ft building on level ground is 25 ft long.

AysviL [449]

Answer:

The shadow is decreasing at the rate of 3.55 inch/min

Step-by-step explanation:

The height of the building = 60ft

The shadow of the building on the level ground is 25ft long

Ѳ is increasing at the rate of 0.24°/min

Using SOHCAHTOA,

Tan Ѳ = opposite/ adjacent

= height of the building / length of the shadow

Tan Ѳ = h/x

X= h/tan Ѳ

Recall that tan Ѳ = sin Ѳ/cos Ѳ

X= h/x (sin Ѳ/cos Ѳ)

Differentiate with respect to t

dx/dt = (-h/sin²Ѳ)dѲ/dt

When x= 25ft

tanѲ = h/x

= 60/25

Ѳ= tan^-1(60/25)

= 67.38°

dѲ/dt= 0.24°/min

Convert the height in ft to inches

1 ft = 12 inches

Therefore, 60ft = 60*12

= 720 inches

Convert degree/min to radian/min

1°= 0.0175radian

Therefore, 0.24° = 0.24 * 0.0175

= 0.0042 radian/min

Recall that

dx/dt = (-h/sin²Ѳ)dѲ/dt

= (-720/sin²(67.38))*0.0042

= (-720/0.8521)*0.0042

-3.55 inch/min

Therefore, the rate at which the length of the shadow of the building decreases is 3.55 inches/min

8 0

3 years ago