Answer:
ergonomists or human factors engineers
Explanation:
Human factors ergonomists or engineers do not have a specific undergraduate degree, but it is important that these professionals have a satisfactory knowledge of anatomy, physiology, anthropometry, biomechanics, psychology, occupational disease, environmental risks, among other subjects. This is because the main function of these professionals is to analyze how people tend to use a product and its design, so that its use will be something natural.
More simply, we can say that these professionals apply their knowledge to improve workplace movements, work environments and training programs.
The cell membrane, cell wall, genetic material, ribosomes.
Basically everything that a bacterium has(because prokaryotes in general don’t have a lot of components and have very simple cells.)
Hope this helps:)
Answer:
Water
Explanation:
Molecular oxygen is the terminal electron acceptor and serves to receive electrons from reduced NADH and FADH2 to reoxidize them. NADH and FADH2 are formed during glycolysis and Kreb's cycle. These reducing powers should be re-oxidized to enter in the first two steps of aerobic respiration again.
For the purpose, NADH, and FADH2 transfer their electrons to the molecular oxygen via electron transport chain. After accepting the electrons, molecular oxygen is oxidized into the water molecule. Therefore, radioactive oxygen isotope would appear in the form of a water molecule after completion of cellular respiration.
Answer: B. Red blood cells released by immune cells cause increased blood flow to the infection site; this increased blood flow brings other red blood cells to the area more quickly.
Answer:
a) 9%.
b) 16.8%.
Explanation:
a).
We are provided with the information that Two linked genes, A and B, are separated by 18 cM (centiMorgan). i.e the recombinant frequency is 18%
Also , the man's genotype is AB/ab... This only result to one explanation, that The man will definitely produce 18% of recombinant gametes which entails
9% Ab & 9% aB
i.e 0.09 Ab & 0.09 aB
On the other-hand, The mother ab/ab have tendency to produce just one single type of gamete which is ab
∴
The probability that their first child will be Ab/ab will be
Pr ( Ab/ab) = (0.09) x (1)
= 0.09
= 9%.
b).
If the father produces 18% of recombinant gametes which entails
9% Ab & 9% aB , this typically implies that the number of the non-recombinant gametes will be;
100%-18% = 82% ( non-recombinant gametes)
i.e genotype AB/ab = 82%
AB =41%; ab = 41%
AB = 0.41 ; ab = 0.41
Now, the probability that their first two children will both be ab/ab:
Using Multiplication Rule to calculate the probability that their first two children (ab/ab); we have:
(0.41)(1) ×(0.41)(1)
= 0.1681
= 16.8%.
