Answer: 4282.928 = 4283 years
Explanation:
Data given;
Carbon 14 half life = 5740
No (initial radiation) = 0.230 Bq/g
Nf (final radiation) = 0.137 Bq/g
First we find the decimal fraction of the remaining half life of the carbon 14
k = No / Nf
k = (0.137 / 0.230) = 0.595652
So to find how many half-life has elapsed, we say
(1/2)^n = k
(1/2) ^n = 0.595652
Therefore
n log 0.5 = log 0.595652
n = ( log 0.595652) / ( log 0.5)
n = 0.747457
To get the elapsed time or how old the sample is;
We say
Carbon 14 half-life × n
5730 yrs × 0.747457
= 4282.928
= 4283 years.
So the sample of the wood is 4283 years old.
The answer to your question is Great Tolerance to a wide range of conditions. Thanks;)
Answer:
False
Explanation:
Facultative anaerobes are organisms that can grow in both the presence or absence of oxygen.
Organism that suffer a poisonous reaction or that can't live in the presence of oxygen are called obligate anaerobes.
Since they are not the same type they would be incompatible and this would cause you're immune system to attack the new blood cells and destroy them. Also known as ABO. Rate this the brainiest please. Thanks.
Because the different environments permit some organisms to thrive, while others cannot. ... Similarly, a fish (extremely suited to its aquatic environment) can't survive out of water. A characteristic which allows growth in one environment will not necessarily allow growth in another.
