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Aleksandr-060686 [28]
3 years ago
14

Pls help meeee!!!!!!: (SAT Prep) In △ABC, AB = BC = 20, DE ≈ 9.28. Approximate BD.

Mathematics
1 answer:
nordsb [41]3 years ago
7 0

if you find problem respond me

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Has a slope of 1/2 and passes<br> through the point (-2, 4).<br> Need the equation please
nikklg [1K]

Answer: Mark me brainliest..

Step-by-step explanation: and imma put the answer inside the comments if you do so. youve got nothing to lose! :D

5 0
3 years ago
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b) How many ways can you deal cards (from a deck of 52) to 4 people when each player gets 7 cards. 2 hidden and 5 visible. Assum
Mariana [72]

Answer:

{52 \choose 7}{45 \choose 7}{38 \choose 7}{31 \choose 7}{7 \choose 2}^4

Step-by-step explanation:

The dealing of the cards can be seen in the following way:

We first have to choose which 7 cards are going to be dealt to the 1st player. So we have to pick 7 cards out of the 52 available cards. This can be done in {52 \choose 7} ways. Now that we have chosen which 7 cards are going to be dealt to the 1st player, we have to choose which 2 of them are going to be the hidden ones. So we have to pick 2 cards out of the 7 cards to be the hidden ones. This can be done in {7 \choose 2} ways. At this point we now know which cards are being dealt to the 1st player, and which ones are hidden for him. Then we have to choose which 7 cards to deal to the 2nd player, out of the remaining ones. So we have to pick 7 out of 52-7=45. (since 7 have been already dealt to the 1st player). This can be done in {45 \choose 7}. Then again, we have to pick which 2 are going to be the hidden cards for this 2nd player. So we have to pick 2 out of the 7. This can be done in {7 \choose 2} ways. Then we continue with the 3rd player. We have to choose 7 cards out of the remaining ones, which at this point are 52-7-7=38. This can be done in {38 \choose 7}. And again, we have to choose which ones are the hidden ones, which can be chosen in {7 \choose 2} ways. Finally, for the last player, we choose 7 out of the remaining cards, which are 52-7-7-7=31. This can be done in {31 \choose 7} ways. And choosing which ones are the hidden ones for this player can be done in {7 \choose 2} ways. At the end, we should multiply all our available choices on each step, to get the total choices or total ways to deal the cards to our 4 players (since dealing the cards is a process of several steps with many choices on each step).

{52 \choose 7}{7 \choose 2}{45 \choose 7}{7 \choose 2}{38 \choose 7}{7 \choose 2}{31 \choose 7}{7 \choose 2}={52 \choose 7}{45 \choose 7}{38 \choose 7}{31 \choose 7}{7 \choose 2}^4

7 0
4 years ago
One plane leaves an hour after another plane. The first plane travels at 400mph. How fast must the second plane travel to catch
Dovator [93]

Answer:

200 mph

Step-by-step explanation:

Ⓗⓘ ⓣⓗⓔⓡⓔ

Plane a: 400mph

Plane b: x mph

2x=400

x=200

(っ◔◡◔)っ ♥ Hope this helped! Have a great day! :) ♥

BTW, brainliest would be greatly appreciated, I only need one more before I advance, thanks!

Also, I may have done something wrong, please tell me if it's incorrect!

4 0
3 years ago
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The length of a rectangular prism is 8
Lena [83]
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replacing the values

250=2*(8*W+8*1+W*1)

250=2*(8*W+8+W)

250=2*(9*W+8)

dived each member by 2

125=9W+8

9W=125-8

9W=117

\boxed{\boxed{W=13~unit~of~measure}}

The volume of a rectangular prism is

V=L*H*W

V=8*1*13

\boxed{\boxed{V=104~unit~of~volume}}
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Answer:

5cm for  each side

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