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3 years ago

Explain how to use the distributive property to find the product (3) 4 1/5

Mathematics

2 answers:

vlada-n [284]3 years ago

8 0

Answer:

Rewrite 3 ( 4 1 /5 ) as 3 ( 4 + 1 5 ) . Distribute the 3 to get 3(4) + 3 ( 1 /5 ) . Multiply to get 12 + 3 /5 . Then add to get 12 3 /5

Step-by-step explanation:

Artist 52 [7]3 years ago

4 0

Answer:

$\frac{63}{5}$

Step-by-step explanation:

Given expression:

(3) 4 $\frac{1}{5}$

The distributive law is mostly applied to multiplication and division which helps to expand a parentheses;

4 $\frac{1}{5}$ can be written as $\frac{21}{5}$

Now;

(3) $\frac{21}{5}$

With distributive property, we simply multiply the two terms;

3 x $\frac{21}{5}$ = $\frac{63}{5}$

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(x+5) (×+5)=49. I need to know what x is, how do I solve this?

Archy [21]

$(x+5)^2=49$
squaer root both sides
x+5=+/-7
minus 5 both sides
x=-5+/-7
x=-5+7=2
x=-5-7=-12

x=2 or -12

4 0

3 years ago

What is the value of (-7 + 3i) - (2-6i)?

BigorU [14]

First you must distribute the minus sign to the number bolded bellow:

(-7 + 3i) - (2 - 6i)

(-7 + 3i) + (-2 + 6i)

-7 + 3i - 2 + 6i

Now you must combine like terms. Imaginary numbers can only combine with imaginary and real number can only be combined with real numbers:

(-7 + (-2) ) + (3i + 6i)

-9 + 9i

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3 years ago

Michael invested 5,000 in an account that has a 5.5% annual interest rate. What equation best describes investment after T years

ivolga24 [154]

Answer:

V = 5000 + 275*T for simple annual interest

or: A = 5000 * (1.055)^T for an annual compound interest

Step-by-step explanation:

I assume this is a simple interest rate. If not I will give the one for compound interest.

V = 5000 + 5000* 0.055 * T (Value of account after T years)

V = 5000 + 275*T for simple annual interest

or: A = 5000 * (1.055)^T for an annual compound interest

5 0

3 years ago

Test the hypothesis using the P-value approach. Be sure to verify the requirements of the test. Upper H 0: pequals0.6 versus U

kow [346]

Answer:

Step-by-step explanation:

From the given information:

The null and the alternative hypothesis can be well written as:

$H_o:P=0.6$

$H_1:P>0.6$

Given that:

n = 200

x = 135

Alpha ∝ = 0.05 level of significance

Then;

⇒ $n \times p\times (1-P)$

= 200 × 0.6 × (1 -0.6)

= 200 × 0.6 × 0.4

= 48 ≥ 10

The sample proportion $\hat P = \dfrac{x}{n}$

$= \dfrac{135}{200}$

= 0.675

The test statistics $Z = \dfrac{\hat P - P}{\sqrt{ \dfrac{P(1-P)}{n} }}$

$Z = \dfrac{0.675 - 0.6}{\sqrt{ \dfrac{0.6 \times 0.4}{200} }}$

$Z = \dfrac{0.075}{\sqrt{ \dfrac{0.24}{200} }}$

Z = 2.165

The P-value = P(Z > 2.165)

= 1 - P(Z < 2.165)

From the z tables

= 1 - 0.9848

= 0.0152

Reject the null hypothesis since P-Value is lesser than alpha. ( i.e. 0.0152 < 0.05).

Thus, there is enough evidence to conclude that the value of the population proportion is greater than 0.6

7 0

3 years ago

Find the area of the figure.

Aloiza [94]

Answer:

Step-by-step explanation:

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2 years ago

Explain how to use the distributive property to find the product (3) 4 1/5​

Explain how to use the distributive property to find the product (3) 4 1/5