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Ronch [10]
3 years ago
5

Help for number 14 it from number 13

Mathematics
1 answer:
anastassius [24]3 years ago
7 0
THE ANSWER IS 42. THANSK KAS;DKFJ; SAKJFS
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How can you quickly determine the number of roots a polynomial will have by looking at the equation?
Alika [10]
Suppose we have a generic polynomial of the form:
 ax ^ 2 + bx + c

 To know how many roots the polynomial can have, the first thing you should do is observe the term of greatest exponent.
 For this case, the term of greatest exponent is 2.
 Therefore, the polynomial has 2 roots.
 Answer:
 
You must observe the term of the polynomial with greater exponent.
8 0
3 years ago
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In a class, 60% of the students are girls. There are 18 girls in the class.
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Answer:

a. Total of 45 students.

b. 18 Boys.

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3 years ago
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An average mosquito found in the environment gives of 12.6 disintigrations per minute per gram of carbon. a preserved mosquito f
lord [1]

From the half life equation, the remaining fraction (\frac{1}{2} )^{\frac{t}{T} }

where t = total time elapsed and T = Half life

Now,  it is given that, T=5730

And remaining fraction is=\frac{1.575}{12.6}

So, substituting these values in the above equation,

\frac{1.575}{12.6}=(\frac{1}{2} )^{\frac{t}{5730} }\\0.125=0.5^{\frac{t}{5730}

Taking log both sides,

log(0.125)=log(0.5)*\frac{t}{5730}

Solving, we obtain that,

t=17190 years

6 0
3 years ago
PLEASE HELP!!!!!The table below shows the data for a random sample of fish that were collected from and later released into a la
dmitriy555 [2]

Answer:B

Step-by-step explanation:

All you have to do is multiply

8 0
3 years ago
You deposited $10,000 in an account. Write an equation to determine the amount, A, you will have in t years if the account pays
Alona [7]

Answer:

10000 x (1.001438)^4t

Step-by-step explanation:

Using the compound interest formula Accrued Amount = P (1 + r/n)^n t

where Accrued amount is to be determined

P = principal; $10000

r = 5.75% = 0.0575

n = number of times interest is applied annually = 4 for quarterly

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Therefore

Accrued Amount (A) = 10000 x (1 + (0.0575/4))^(4t)

= 10000 x (1 + (0.001438))^(4t)

= 10000 x (1.001438)^4t

which can then be solved by varying t, the number of years

3 0
3 years ago
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