Step-by-step explanation:
Slope = y2-y1 / X2-x1
= 8-4/2-(-3)
=4/5
Answer:
k=-8
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
Answer:
This linear system has one solution.
Step-by-step explanation:
First equation: y = x + 2
Second equation: 6x - 4y = -10
Let's change the second equation in slope-intercept form y = mx + b.
<u>Slope-intercept form</u>
y = mx + b
m ... slope
b ... y-intercept
If two lines have the <em>same slope </em>but <em>different y-intercept</em>, they are parallel - <u>system has no solutions</u>.
If two lines have the <em>same slope</em> and the <em>same y-intercept</em>, they are the same line and are intersecting in infinite many points - <u>system has infinite many solutions</u>.
If two lines have <em>different slopes</em> then they intersect in one point - <u>system has one solution</u>.
We see that lines have different slopes. First line has slope 1 and the other line has slope . So the system has one solution.
You can also check this by solving the system.
Substitute y in second equation with y from first.
6x - 4y = -10
6x - 4(x + 2) = -10
Solve for x.
6x - 4x - 8 = -10
2x = -2
x = -1
y = x + 2
y = -1 + 2
y = 1
The lines intersect in point (-1, 1). <-- one solution
Horizontal- y=-1/2
vertical- x=5
x intercepts- (-2,0)
y intercepts- none
hole- (0, 1/5)
Givens
Let the number of students in the class be x
Let the number of pieces of gum she gave out be 3x
Equation
3x + 8 = 168 This will not work out evenly. Let's try x - 1. The reason for that is because she may not give out anything to herself.
3(x - 1) + 8 = 168 This doesn't work either.
Well we have to choose. It's a rounding problem.
3x + 8 = 168 Subtract 8 from both sides.
3x = 168 - 8 Combine
3x = 160 Divide by 3 on both sides.
x = 160 / 3
x = 53.333333333
Since that can't be, we could say there were 53 students.
3x