There are 4 red balls and 2 blue balls in a box. you pick 3 balls, one after another without replacing the balls picked. what is
the probability the first 2 balls are red and the last one blue?
2 answers:
Im gonna guess a 35% chance
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Answer:
a
Step-by-step explanation:
because the rest aren't true
The answer will be 752.50
That is false because you have to subtract the exponents not divide
1. 3h+11
2. -2r
3. g-4
4. 5f+4
5. 15z
Answer:
1.)C
2.)A
3.)B
4.)B
5.)A
Step-by-step explanation:
BTW if it's EASY then try but anyway,there you go!!
