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Lana71 [14]
3 years ago
13

Find the sum and express it in the simplest form (-2y-4x+7)+(-4y+x-1)

Mathematics
2 answers:
Butoxors [25]3 years ago
8 0

Answer:

-6y - 3x + 6

Step-by-step explanation:

All you are doing is combining like-terms the whole way.

I am joyous to assist you anytime.

Marina86 [1]3 years ago
3 0

Y=7+2x......(1)

put this value in 4y+x=1

4(7+2x)+x=1

28+14x+x=1

15x=-27

x=-27/15.....(2)

put this value in eqn (1)

y=7+2(-27/5)

y=7-54/5

y=-3.8

I really hope this helps :D:D:D!!!!

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Please help, need answer ASAP! Will give brainliest to correct answer!
Ilya [14]

Answer:

Second option is the right choice.

Step-by-step explanation:

Divide the second equation by -5 and you'll get the equation same as first equation.

\frac{5x}{-5}-\frac{20y}{-5}=\frac{-5}{-5}\:\:\:\rightarrow \:\:\:-x+4y=1

So, it has infinite many solutions.

6 0
3 years ago
Alexa borrows $10,000 from her aunt and they agree Alexa will pay her back including 5% simple interest. How much more will Alex
zavuch27 [327]

Answer:

46.73

Step-by-step explanation:

10000(5)75/)57)/83)’lsh “32=46.73

3 0
3 years ago
7 times a number is 8 less than the square of that number. Find the negative solution.
charle [14.2K]

Answer:

  -1

Step-by-step explanation:

The required relation is ...

  7n = n^2 -8

  0 = n^2 -7n -8 . . . . put in standard form

  0 = (n -8)(n +1) . . . . factor

Solutions are n=8 and n=-1.

The negative solution is -1.

7 0
3 years ago
Fifty identical balls are numbered 1 through 50 and placed in a bucket. Then, a ball is randomly selected from the bucket. Selec
Drupady [299]

Answer:

Blank 1: 0.12

Blank 2: 0.18

Step-by-step explanation:

Out of 50, there are 6 numbers that contain the digit 5, (5, 15, 25, 35, 45, 50)

so when you take 0.06 and multiply it by 2 (because you have to multiply 50 by 2 to get 100), you get 0.12.

For blank 2, there are 9 single digit numbers, (1, 2, 3, 4, 5, 6, 7, 8, and 9) equaling 0.09. Multiply that by 2 and you get 0.18.

8 0
3 years ago
What are the coordinates of the endpoints of the midsegment for DEF that is parallel to DE
Nutka1998 [239]

Answer:

\left(\dfrac{x_D+x_F}{2},\dfrac{y_D+y_F}{2}\right),  \left(\dfrac{x_E+x_F}{2},\dfrac{y_E+y_F}{2}\right).

Step-by-step explanation:

Let points D, E and F have coordinates (x_D,y_D),\ (x_E,y_E) and (x_F,y_F).

1. Midpoint M of segment DF has coordinates

\left(\dfrac{x_D+x_F}{2},\dfrac{y_D+y_F}{2}\right).

2. Midpoint N of segment EF has coordinates

\left(\dfrac{x_E+x_F}{2},\dfrac{y_E+y_F}{2}\right).

3. By the triangle midline theorem, midline MN is parallel to the side DE of the triangle DEF, then points M and N are endpoints of the midsegment for DEF that is parallel to DE.

6 0
3 years ago
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