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Maurinko [17]
3 years ago
15

Anita sells stuffed bunnies and puppies to a toy store. She sells each bunny for $8.00 and each puppy for $10.00. This week, Ani

ta wants to sell more than 30 stuffed animals and needs to earn a minimum of $450.
Which system of inequalities can Anita use to determine the number of stuffed bunnies, x, and stuffed puppies, y, that she can sell to meet her goals?

A. x + y > 30
8x + 10y ≥ 450

B. x + y > 30
8x + 10y ≤ 450

C. x + y < 30
8x + 10y ≥ 450

D. x + y < 30
8x + 10y ≤ 450
Mathematics
1 answer:
katrin2010 [14]3 years ago
3 0

Answer:

A. x + y > 30

8x + 10y ≥ 450

Step-by-step explanation:

x = bunnies

y = puppies

X + Y = more than 30 = X+Y >30

1 bunny equals $8.00

1 puppy equals $10.00

so, 8x + 10y= at least $450 = 8x + 10y  ≥ $450

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PIT_PIT [208]

Answer:y=8x

Step-by-step explanation:

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3 years ago
Find the product.
tankabanditka [31]

the answer would be c

8 0
3 years ago
Read 2 more answers
Plz help i have to submit in 20 minutes !!!
amm1812

Answer:

Step-by-step explanation:

1. a). Hypotenuse² = (Leg 1)² + (Leg 2)²

       h² = 10² + 24²

       h = √676

       h = 26

 (b). Hypotenuse² = (Leg 1)² + (Leg 2)²

       (25)² = (15)² + (leg 2)²

       Leg 2 = √(625 - 225)

                 = √400

                 = 20

  (c). Hypotenuse² = (Leg 1)² + (Leg 2)²

        h² = 4² + 6²

        h = √(16 + 36)

        h = √52

        h = 2√13

  (d). Hypotenuse² = (Leg 1)² + (Leg 2)²

        (14)² = (Leg 1)² + 7²

         Leg 1 = √(196 - 49)

                   = √147

                   = 7√3

2). Hypotenuse² = (Leg 1)² + (Leg 2)²

    Leg 1 = leg 2 = 7 units [Since, triangle is an isosceles triangle]

    h² = 7² + 7²

    h = √98

    h = 7√2

    Option (1) is the correct option.

3). Hypotenuse² = (Leg 1)² + (Leg 2)²

    (26)² = (Leg 1)² + (10)²

    Leg 1 = √(676 - 100) = 24

    Area of a right triangle = \frac{1}{2}(\text{Leg 1})(\text{Leg 2})

                                           = \frac{1}{2}(24)(10)

                                           = 120 square units

     Option (3) is the correct option.

8 0
3 years ago
Pqr is similar to xyz what is the perimeter of xyz? A.21cm B.63cm C. 105cm D.126cm
skelet666 [1.2K]

Answer:

option D. 126 cm

Step-by-step explanation:

step 1

Find the scale factor

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional and this ratio is called the scale factor

In this problem

Triangles PQR and XYZ are similar by AA Similarity Theorem

so

\frac{XY}{PQ}=\frac{YZ}{QR}=\frac{XZ}{PR}

Let

z ---> the scale factor

z=\frac{XY}{PQ}

substitute the given values

z=\frac{30}{5}=6

step 2

Find the perimeter of triangle XYZ

we know that

If two figures are similar, then the ratio of its perimeters is equal to the scale factor

Let

z ----> the scale factor

p_1 ----> the perimeter of triangle XYZ

p_2 ---> the perimeter of triangle PQR

so

z=\frac{p_1}{p_2}

The perimeter of triangle PQR is

p_2=5+10+6=21\ cm

we have

z=6\\p_2=21\ cm

substitute

6=\frac{p_1}{21}

p_1=6(21)=126\ cm

therefore

The perimeter of triangle XYZ is 126 cm

5 0
3 years ago
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