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Mashutka [201]
3 years ago
8

Brian, Kirk, and Jim established a partnership with equal capital contributions. However, Kirk provided an additional contributi

on in the form of a loan to the company. Which of the following is true?
A) Brian can withdraw capital advances from the partnership
B) Jim and Brian can prevent Kirk from withdrawing advances from the partnership.
C) Kirk and Brian can prevent Jim from withdrawing advances from the partnership.
D) Jim can withdraw capital advances from the partnership.
Business
1 answer:
luda_lava [24]3 years ago
3 0

Answer:

B)

Explanation:

In this specific scenario, the term that is true is that Jim and Brian can legally prevent Kirk from withdrawing advances from the partnership. This is because all three of them entered into a partnership with equal contributions meaning that they all own the same percentage of the company and must all agree on things before they are done. Even though Kirk provided an additional contribution, this was a loan which will be paid back eventually but does not give kirk any extra power in the company and must discuss decisions with Brian and Jim before it can be done.

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The following data apply to Elizabeth's Electrical Equipment: Value of operations $20,000 Short-term investments $1,000 Debt $6,
Liula [17]

Answer:

b. $50.00

Explanation:

Intrinsic per share stock price immediately after the repurchase will be $50

4 0
3 years ago
What aspect of project management was omitted from the PMI definition that is included in the definition proposed by Meredith an
Illusion [34]

Answer:

Fulfilling client expectations

Explanation:

Fulfilling client's expectations is one of the potent ways an organization can achieve its long term corporate objective. If I were on the PMI decision making body, I would not have outrightly voted for its inclusion. What I will do, however, is to:

1. fully gain an understanding of best practices and procedures that could be applied to achieve the client's expectations.

2. Prototype such procedures, practices and processes and assess its impact on the long term corporate objective.

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6 0
3 years ago
The College Board reported the following mean scores for the three parts of the Scholastic Aptitude Test (SAT) (The World Almana
storchak [24]

Answer:

a) P(492

And we can use excel or the normal standard table to find this probability:

P(-0.949 < Z< 0.949)= P(Z

b) P(505

And we can use excel or the normal standard table to find this probability:

P(-0.949 < Z< 1.898)= P(Z

c) P(484

And we can use excel or the normal standard table to find this probability:

P(-1 < Z< 1)= P(Z

Explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the scores for critical reading of a population, and for this case we know the distribution for X is given by:

X \sim N(502,100)  

Where \mu=502 and \sigma=100

We select a sample of size n=90, since the distribution for X is normal then the distribution for the sample size is also normal

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}}=\frac{100}{\sqrt{90}}=10.54)

And for this case we want this probability:

P(502-10 < \bar X < 502+10)

And for this case we can use the z score given by:

z= \frac{\bar X -\mu}{\sigma_{\bar x}}

And if we use this formula we got:

P(492

And we can use excel or the normal standard table to find this probability:

P(-0.949 < Z< 0.949)= P(Z

Part b

Let X the random variable that represent the scores for Math of a population, and for this case we know the distribution for X is given by:

X \sim N(515,100)  

Where \mu=515 and \sigma=100

We select a sample of size n=90, since the distribution for X is normal then the distribution for the sample size is also normal

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}}=\frac{100}{\sqrt{90}}=10.54)

And for this case we want this probability:

P(515-10 < \bar X < 515+10)

And for this case we can use the z score given by:

z= \frac{\bar X -\mu}{\sigma_{\bar x}}

And if we use this formula we got:

P(505

And we can use excel or the normal standard table to find this probability:

P(-0.949 < Z< 1.898)= P(Z

Part c

Let X the random variable that represent the scores for Writing of a population, and for this case we know the distribution for X is given by:

X \sim N(494,100)  

Where \mu=494 and \sigma=100

We select a sample of size n=100, since the distribution for X is normal then the distribution for the sample size is also normal

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}}=\frac{100}{\sqrt{100}}=10)

And for this case we want this probability:

P(494-10 < \bar X < 494+10)

And for this case we can use the z score given by:

z= \frac{\bar X -\mu}{\sigma_{\bar x}}

And if we use this formula we got:

P(484

And we can use excel or the normal standard table to find this probability:

P(-1 < Z< 1)= P(Z

3 0
3 years ago
The most popular approach to increase goal commitment is to:________
nexus9112 [7]

Answer:

C encourage employee participation while setting goals.

Explanation:

Goals are ideas in which an individual or group of people or organization aim to achieve within a stipulated time.

While top managements of organizations are saddled with the responsibility of setting goals and cascaded to lower managers and subsequently junior employees, it is now essential that employees are encouraged to participate in these goal settings.

By involving employees in goal settings, there would be increase in goals commitment thereby leading to dedication amongst employees and subsequently results to attainment of such goals.

5 0
3 years ago
Suppose the​ risk-free return is 6.5 % and the market portfolio has an expected return of 10.3 % and a standard deviation of 16
CaHeK987 [17]

Answer:

= 7.678%

Explanation:

Data provided

Risk free rate = 6.5%

Beta = 0.31

Marker return rate = 10.3%

Risk free rate = 6.5%

The computation of expected return is shown below:-

Expected return = Risk free rate + Beta × (Marker return rate - Risk free rate)

= 6.5% + 0.31 × (10.3% - 6.5%)

= 6.5% + 0.31 × (3.8%)

= 6.5% + 1.178%

= 7.678%

4 0
3 years ago
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