let the other angle be x degree
bigger angle = x +36°
According to the question,
x+36° + x° = 180°
=> 2x = 180–36
=> x = 144/2
=> x = 72°
Measure of the bigger angle = x + 36
= 72° + 36°
= 108°
Answer:
4x^5−15x^3−11x−1
Step-by-step explanation:
Simplify the expression. 4x^5−15x^3−11x−1
C because i took the test
<h3>Given</h3>
tan(x)²·sin(x) = tan(x)²
<h3>Find</h3>
x on the interval [0, 2π)
<h3>Solution</h3>
Subtract the right side and factor. Then make use of the zero-product rule.
... tan(x)²·sin(x) -tan(x)² = 0
... tan(x)²·(sin(x) -1) = 0
This is an indeterminate form at x = π/2 and undefined at x = 3π/2. We can resolve the indeterminate form by using an identity for tan(x)²:
... tan(x)² = sin(x)²/cos(x)² = sin(x)²/(1 -sin(x)²)
Then our equation becomes
... sin(x)²·(sin(x) -1)/((1 -sin(x))(1 +sin(x))) = 0
... -sin(x)²/(1 +sin(x)) = 0
Now, we know the only solutions are found where sin(x) = 0, at ...
... x ∈ {0, π}