The solution for the system of linear equations 2x- y = 3 and y - x = 1 are x = 4 and y = 5
<h3>What are linear equations?</h3>
Linear equations are equations that have constant average rates of change, slope or gradient
<h3>How to determine the solution to the system?</h3>
A system of linear equations is a collection of at least two linear equations.
In this case, the system of equations is given as
2x- y = 3
y - x = 1
Make y the subject in the second equation, by adding x to both sides of the equation
y - x + x = x + 1
This gives
y = x + 1
Substitute y = x + 1 in 2x- y = 3
2x- x - 1 = 3
Evaluate the like terms
x = 4
Substitute x = 4 in y = x + 1
y = 4 + 1
Evaluate
y = 5
Hence, the solution for the system of linear equations 2x- y = 3 and y - x = 1 are x = 4 and y = 5
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Answer:
f(-3) = 16
Step-by-step explanation:
You substitute -3 to x.
f(-3) = 2(-3)² - 5(-3) - 17
f(-3) = 16.
As for the coordinates, the coordinates plotted in the graph above are (1,-1) and (2,-2).
5 times 5..........................
Answer:
729
Step-by-step explanation:
Define unit vectors along the x-axis and the y-axis as
respectively.
Then the vector from P to Q is
In component form, the vector PQ is (-8,5).
The magnitude of vector PQ is
√[(-8)² + 5²] = √(89) = 9.434
Answer:
The vector PQ is (-8, 5) and its magnitude is √89 (or 9.434).
