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Lera25 [3.4K]
3 years ago
12

99 POINTS BRAINLIEST!!! No fake answers!

Mathematics
2 answers:
Strike441 [17]3 years ago
7 0

The mean for a binomial substitution = n x p

Mean = 1632 x 0.57 = 930.24

The answer would be D.

Picture:

Multiply P(x) by X, then add those together:

0 x 0.42 = 0

1 x 0.12 = 0.12

2 x 0.34 = 0.68

3 x 0.05 = 0.15

4 x 0.07 = 0.28

Mean = 0 + 0.12 + 0.68 + 0.15 + 0.28 = 1.23

luda_lava [24]3 years ago
6 0

Answer:

The mean of a binomial distribution is given  by  mean  = n x p where n = the number of items and p equals the probability of success.  Here we have:

mean =  1632 x 0.57  =   930.2

Step-by-step explanation:

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4 years ago
Write the linearization of the function at the points indicated. (Enter your answer as an equation. Let x be the independent var
Natalija [7]

Answer:

\displaystyle y=5+\frac{x}{10}

\displaystyle y=10+\frac{(x-75)}{20}

Step-by-step explanation:

<u>Linearization</u>

It consists of finding an approximately linear function that behaves as close as possible to the original function near a specific point.

Let y=f(x) a real function and (a,f(a)) the point near which we want to find a linear approximation of f. If f'(x) exists in x=a, then the equation for the linearization of f is

y=f(x)=f(a)+f'(a)(x-a)

Let's find the linearization for the function

y=\sqrt{25+x}

at (0,5) and (75,10)

Computing f'(x)

\displaystyle f'(x)=\frac{1}{2\sqrt{25+x}}

At x=0:

\displaystyle f'(0)=\frac{1}{2\sqrt{25+0}}=\frac{1}{10}

We find f(0)

f(0)=\sqrt{25+0}=5

Thus the linearization is

\displaystyle y=f(0)+f'(0)(x-0)=5+\frac{1}{10}x

\displaystyle y=5+\frac{x}{10}

Now at x=75:

\displaystyle f'(75)=\frac{1}{2\sqrt{25+75}}=\frac{1}{20}

We find f(75)

f(75)=\sqrt{25+75}=10

Thus the linearization is

\displaystyle y=f(75)+f'(75)(x-75)=10+\frac{1}{20}(x-75)

\displaystyle y=10+\frac{(x-75)}{20}

5 0
3 years ago
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Maksim231197 [3]

Answer:

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Step-by-step explanation:

<u>Given</u>

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<u>Solution for f(3)</u>

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6 0
3 years ago
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