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AleksAgata [21]
3 years ago
6

Showing algebraic support, find the value of x.

Mathematics
1 answer:
Travka [436]3 years ago
3 0

Answer:

x = 52.5

Step-by-step explanation:

The triangle on the left has 2 congruent sides, thus is isosceles

The base angles of an isosceles triangle are also congruent, thus

x = \frac{180-75}{2} = \frac{105}{2} = 52.5

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Calculate the side lengths a and b to two decimal places.
Strike441 [17]

Answer:

A.)=24.78

B.)=26

C.)=7.33

D.)=25.44

Step-by-step explanation:

A.)11.40+13.38=24.78

B.)11+15=26

C.)4.18+3.15=7.33

D.)10.92+14.52=25.44

7 0
2 years ago
Read 2 more answers
The figure below is composed of two right angles. what is the area of the figure in square inches?​
Akimi4 [234]

Answer:

16

Step-by-step explanation:

16 square inches. when u do multiply you just get it so yeah

8 0
3 years ago
The triangular-shaped bases of a prism are 24 cm in length and have a height of 35 cm. Each side is 37 cm. The height of the pri
Savatey [412]

Answer:

The surface area of Triangular base Prism = 3682 cm²

Step-by-step explanation:

Given in question as :

For a Triangular base prism ,

The base of  prism (b) = 24 cm

The height of prism (l) = 29 cm

Each side length (s) = 37 cm

The height of base triangle ( h ) = 35 cm

Hence , we know that The surface area of Triangular base prism is

 = (b×h) + (2×l×s) + (l×b)

 = (24×35) + (2×29×37) + (29×24)

 = (840) + (2146) + (696)

 = 3682  cm²

Hence The surface area of Triangular base Prism is 3682 cm²  Answer

3 0
3 years ago
The table shows the distance Allison drove on one day of her vacation. Is the relationship between the distance and the time a p
Anuta_ua [19.1K]

Answer:

we conclude that the relationship between distance and time is NOT proportional.

Hence, she did not drive at a constant speed.

Step-by-step explanation:

We know that when 'y' varies directly with 'x', we get the equation

y ∝ x

y = kx

k = y/x

where 'k' is called the constant of proportionality.

In our case, the table shows the distance Allison drove on one day of her vacation.

Time (h)              1         2        3          4        5

Distance (mi)       55    100     165     280    250

using the equation

k = y/x

susbtitute y = 55, x = 1

k = 55/1 = 55

substitute y = 100, x = 2

k = y/x

k = 100 / 2 = 50

substitute y = 165, x = 3

k = y/x

k = 165 / 3 = 55

substitute y = 280, x = 4

k = y/x

k = 280 / 4 = 70

substitute y = 250, x = 5

k = y/x

k = 250 / 5 = 50

It is clear that the value of 'k' does not remain constant.

Therefore, we conclude that the relationship between distance and time is NOT proportional.

Hence, she did not drive at a constant speed.

6 0
3 years ago
Find the area of the triangle
BARSIC [14]

Answer:

The Area of Δ ABC = 219.13

Step-by-step explanation:

<em>The hard part about this problem is finding the area without the height</em>

The formula to do this is Area = \sqrt{S(S-A)(S-B)(S-C)}

A, B, C represent the sides

S represents \frac{1}{2} (A + B + C)

In this equation, we will make the base be A, and the other two sides will be B and C

<u>Sides B and C are the same length</u> because they meet at a 90° angle

Lets plug the numbers into the variables

A = 28

B= 21

C= 21

<u>Remember:</u> S represents  \frac{1}{2}  (A + B + C)

S =  \frac{1}{2} (28 + 21 + 21)

S =  \frac{1}{2} (70)

S = 35

<em>Lets plug the numbers into the Area Formula now!</em>

Area = \sqrt{35(35 - 28)(35 - 21)(35 - 21)}

According to the order of operations, we need to do the calculations in parentheses <u>first</u>

35 - 28 = 7

35 - 21 = 14

35 - 21 = 14

14 x 14 x 7 = 1372

1372 x 35 = 48020

\sqrt{48020} = 219.13

The Area of Δ ABC = 219.13

3 0
3 years ago
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