3 years ago

The length of a rectangle is 5 less than twice the width. Find the dimensions if the perimeter is 110?

1 answer:

8 0

Let, Width = x
Length = 2x - 5

So, perimeter = 110 = 2(l+w)
110 = 2(2x-5+x)
110 = 2(3x-5)
110 = 6x-10
6x = 110+10
x = 120/6
x = 20
So, 2x-5 = 2(20)-5 = 35

So, dimensions are 35 × 20

Hope this helps!

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