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3 years ago

Suppose you have 15 muffins. How many muffins are left after you give a friend 1/3 of them?

Mathematics

2 answers:

madam [21]3 years ago

5 0

You would have 10 muffins left because 1/3 of 15 is 5 so 15-5=10

Makovka662 [10]3 years ago

4 0

If you split 15 muffins into 3 groups, youre going to have 5 muffins in each group. so if you give a friend 1 out of the 3 groups, youre going to have 10 muffins left.

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Please answer 1-5 you can copy and paste then add answer 1.= 2.= 3.= 4.= 5.=

kherson [118]

Answer:

1) 2500

2)1:500

3)500,1000,1500,2000.....

4)lable the axis

5) 6000

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

I have a question about polynomial division it is in the picture

Cloud [144]

To answer this question, we have to do the long division process for polynomials. We can do the operation as follows:

To do this division process, we have:

1. Divide the first term of the dividend by the first element of the divisor. They are:

$\frac{-4x^3}{4x^2}=-x$

2. Now, we have to multiply this result by the divisor, and the result will change its sign since we have to subtract that result from the dividend as follows:

$-x\cdot(4x^2_{}-4x-4)=-4x^3+4x^2+4x$

And since we to subtract this result from the dividend, we end up with:

$-(-4x^3+4x^2+4x)=4x^3-4x^2-4x$

3. Then we have the following algebraic addition:

$\frac{\begin{cases}-4x^3+24x^2-15x-15 \\ 4x^3-4x^2-4x\end{cases}}{20x^2-19x-15}$

4. Again, we need to divide the first term of the dividend by the first term of the divisor as follows:

$\frac{20x^2}{4x^2}=5$

5. And we have to multiply 5 by the divisor, and the result will be subtracted from the dividend:

$5\cdot(4x^2-4x-4)=20x^2-20x-20$

Since we have to subtract this from the dividend, we have:

$-(20x^2-20x-20)=-20x^2+20x+20$

6. And we have to add this algebraically to the dividend we got in the previous step:

$\frac{\begin{cases}20x^2-19x-15 \\ -20x^2+20x+20\end{cases}}{x+5}$

And this is the remainder of the division, x + 5.

As we can see from the division process, we got as:

1. The quotient: -x + 5

$q=-x+5$

2. The remainder: x + 5.

$R=x+5$

Since we have that the dividend = divisor * quotient + remainder.

Therefore, the result for this division is:

$-4x^3+24x^2-15x-15=(4x^2-4x-4)\cdot(-x+5)+(x+5)$

4 0

1 year ago

Let f be a differentiable function such that f(0) = -5 and f'(x) is less than or equal to 3 for all x. Of the following, which i

stepladder [879]

E) 2
Remember that the first derivative of a function is the slope of the function at any specified point. We've been told that f(0) = -5 and that f'(x) is always less than or equal to 3. So let's look at the available options and see what the average slope would have to be in order to get the specified value of f(2).
A) -10: (-10 - -5)/(2 - 0) = -5/2 = -2.5
B) -5: (-5 - -5)/(2 - 0) = 0/2 = 0
C) 0: (0 - -5)/(2 - 0) = 5/2 = 2.5
D) 1: (1 - -5)/(2 - 0) = 6/2 = 3
E) 2: (2 - -5)/(2 - 0) = 7/2 = 3.5
Now taking into consideration the mean value theorem, the value of the function f'(x) has to have the value equal to the average slope between the two points at at least one point between the two given values. For options A, B, C, and D it's possible for f'(x) to return values that make that slope possible. However, for option E, the mean value theorem indicates that f'(x) has to have the value of 3.5 for at least 1 point between x=0 and x=2. And since we've been told that f'(x) is less than or equal to 3 for all possible values of x, that is in conflict and f(2) can not have the value of 2.

3 0

3 years ago

The solution to 5-3x> 35 is either x >-10 or -10> x which solution is correct

maw [93]

Answer:

x < - 10

Step-by-step explanation:

Given

5 - 3x > 35 ( subtract 5 from both sides )

- 3x > 30

Divide both sides by - 3, reversing the symbol as a result of dividing by a negative quantity.

x < - 10 Or - 10 > x

6 0

3 years ago

The data represent the age of world leaders on their day of inauguration. Find the five-number summary, and construct a boxplot

Mumz [18]

Answer:

Minimum value = 43, $Q_1=52$ , $Q_2=Median=61$ , $Q_3=67$ , Maximum value = 69.

Distribution is negative skewed.

Step-by-step explanation:

The given data set is

44, 43, 67, 68, 57, 65, 52, 62, 69, 54, 53, 61, 67, 48, 65

Arrange the data in ascending order

43, 44, 48, 52, 53, 54, 57, 61, 62, 65, 65, 67, 67, 68, 69

Divide the data in 4 equal parts.

(43, 44, 48), 52, (53, 54, 57), 61, (62, 65, 65), 67, (67, 68, 69)

Minimum value = 43

$Q_1=52$

$Q_2=Median=61$

$Q_3=67$

Maximum value = 69

Starting and end point of box plot represent the minimum and maximum value respectively. Box starts from the first quartile to the third quartile. A vertical line goes through the box at the median.

The shape of the distribution.

Normally distributed: If $Q_3-Q_2=Q_2-Q_1$