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3 years ago

The following statement is false. Rewrite the statement to make it true.

Mathematics

1 answer:

Ksju [112]3 years ago

6 0

we are given

$\sum _{n=0}^55n\:$

we can see that

n starts from 0 and goes to 5

so, there are 6 terms

that's why this statement is false

so, true statement can be written as

The are six terms in the series equation.........Answer

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What is the product of 2x2 + 4x - 2) and (3x+6) ?

TiliK225 [7]

Answer:

Step-by-step explanation:

2x2+4x-2)

Answer is -32

7 0

3 years ago

Write a<br> as a repeating decimal.<br> Write 2/5 as a repeating decimal.

Svet_ta [14]

Answer:

0.4

Step-by-step explanation:

2/5 = 4/10

4/10 = 0.4

2/5 is not a repeating decimal.

Hope This Helps :)

6 0

3 years ago

Read 2 more answers

Type the correct answer for each.

xxTIMURxx [149]

If point $\left(x,\ \frac{\sqrt{7}}{3}\right)$ is on the unit ircle, then:

$x^2+\left( \frac{ \sqrt{7} }{3} \right)^2=1 \\ \\ \Rightarrow x^2+ \frac{7}{9} =1 \\ \\ \Rightarrow x^2=1- \frac{7}{9} = \frac{2}{9} \\ \\ \Rightarrow x= \sqrt{ \frac{2}{9} } = \frac{ \sqrt{2} }{3}$

Since, the point is in the second quadrant, x is negative.

Thus, $(x,\ y)=\left(x,\ \frac{\sqrt{7}}{3}\right)=\left(-\frac{ \sqrt{2} }{3},\ \frac{\sqrt{7}}{3}\right)$

Part A:

$3 \sqrt{7} =6\left( \frac{ \sqrt{7} }{2} \right) \\ \\ =6\left( \frac{ \sqrt{7} }{3} \cdot \frac{3}{ \sqrt{2} } \right) \\ \\ =6\left( \frac{ \frac{ \sqrt{7} }{3} }{ \frac{ \sqrt{2} }{3} } \right)=-6\left( \frac{ \frac{ \sqrt{7} }{3} }{ -\frac{ \sqrt{2} }{3} } \right) \\ \\ =-6\left( \frac{y}{x} \right)=-6\tan\theta$

Therefore, $-6\tan\theta=3\sqrt{7}$ .

Part B:

$- \frac{ \sqrt{7} }{2} =- \frac{ \sqrt{7} }{3} \cdot \frac{3}{ \sqrt{2} } \\ \\ =- \frac{ \frac{ \sqrt{7} }{3} }{ \frac{ \sqrt{2} }{3} } = \frac{ \frac{ \sqrt{7} }{3} }{ -\frac{ \sqrt{2} }{3} } = \frac{y}{x} \\ \\ =\tan\theta$

Therefore, $\tan\theta=- \frac{ \sqrt{7} }{2}$

8 0

3 years ago

Select all the correct answers.

evablogger [386]

Answer:
The 3rd and 4th option

Explanation:
A function only works when the input (x) only has one output (y).
The first, second, and the last option has the input has two or more outputs.

Fun Fact:
It is okay for the outputs to have more then in input, but not okay for the input to have more then one output.

I hope this help and have a nice day :)

6 0

3 years ago

Y = mx + b

Yuki888 [10]

The last option, the y-intercept.

5 0

3 years ago