Ask question

Ask question

All categories

3 years ago

7

It's easy 5th-grade math please solve the whole problem (the whole backside is the problem u can look I will mark the brainiest.

..

1 answer:

blondinia [14]3 years ago

5 0

Answer:

which question is it? and please take the picture from the top.

Step-by-step explanation:

And Also will answer in the replies.

You might be interested in

What number is 1000 less than 921, 438 and explain your answer

aleksley [76]

The number 1000 less than 921,438 is 920,438. What you do is take 921,438 and subtract 1000 from it.

7 0

3 years ago

Read 2 more answers

I’m so bad at this pls-

dolphi86 [110]

Answer:

$5 \sqrt{2}$

Step-by-step explanation:

$\sqrt{5} \times \sqrt{10} \\ = \sqrt{5} \times \sqrt[]{5} \times \sqrt{2} \\ = 5\sqrt{2}$

<h3>Hope it is helpful....</h3>

3 0

3 years ago

Read 2 more answers

Chris’s bank allows him to have a negative balance in his checking account. Chris initially has $450 in his account. He then wri

Cloud [144]

x=Money after withdrawals.

x=450-200(3)

x=450-600

x=-250

After making 3 $200 withdrawals from his account after initially starting with $450 he has a balance of negative $250 in his account.

4 0

3 years ago

If the sum of the zereos of the quadratic polynomial is 3x^2-(3k-2)x-(k-6) is equal to the product of the zereos, then find k?

lys-0071 [83]

Answer:

2

Step-by-step explanation:

So I'm going to use vieta's formula.

Let u and v the zeros of the given quadratic in ax^2+bx+c form.

By vieta's formula:

1) u+v=-b/a

2) uv=c/a

We are also given not by the formula but by this problem:

3) u+v=uv

If we plug 1) and 2) into 3) we get:

-b/a=c/a

Multiply both sides by a:

-b=c

Here we have:

a=3

b=-(3k-2)

c=-(k-6)

So we are solving

-b=c for k:

3k-2=-(k-6)

Distribute:

3k-2=-k+6

Add k on both sides:

4k-2=6

Add 2 on both side:

4k=8

Divide both sides by 4:

k=2

Let's check:

$3x^2-(3k-2)x-(k-6) \text{ with }k=2$ :

$3x^2-(3\cdot 2-2)x-(2-6)$

$3x^2-4x+4$

I'm going to solve $3x^2-4x+4=0$ for x using the quadratic formula:

$\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\frac{4\pm \sqrt{(-4)^2-4(3)(4)}}{2(3)}$

$\frac{4\pm \sqrt{16-16(3)}}{6}$

$\frac{4\pm \sqrt{16}\sqrt{1-(3)}}{6}$

$\frac{4\pm 4\sqrt{-2}}{6}$

$\frac{2\pm 2\sqrt{-2}}{3}$

$\frac{2\pm 2i\sqrt{2}}{3}$

Let's see if uv=u+v holds.

$uv=\frac{2+2i\sqrt{2}}{3} \cdot \frac{2-2i\sqrt{2}}{3}$

Keep in mind you are multiplying conjugates:

$uv=\frac{1}{9}(4-4i^2(2))$

$uv=\frac{1}{9}(4+4(2))$

$uv=\frac{12}{9}=\frac{4}{3}$

Let's see what u+v is now:

$u+v=\frac{2+2i\sqrt{2}}{3}+\frac{2-2i\sqrt{2}}{3}$

$u+v=\frac{2}{3}+\frac{2}{3}=\frac{4}{3}$

We have confirmed uv=u+v for k=2.

4 0

3 years ago

Write the equation of the line, in standard form, that has an x-intercept of 2 and is parallel to 2x + y = -5. Include your work

STALIN [3.7K]

Paralell to 2x+y=-5
means it has same slope
means it is in form
2x+y=c where we have to find c
convert to slope intercept
minus 2x both sides

xint of 2
xint is where th eline crosses the x axis or where y=0, x=2

2(2)+0=c
2(2)=c
4=c

the equation is 2x+y=4

4 0

3 years ago