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musickatia [10]
3 years ago
8

Let m = 6x + 5.

Mathematics
1 answer:
arsen [322]3 years ago
5 0

We have been given that m=6x+5. We are asked to write (6x + 5)^2-10 =-18x-15 in terms of m.

First of all, we will factor -3 from right side of equation as:

(6x + 5)^2-10 =-3\cdot 6x-3\cdot 5

(6x + 5)^2-10 =-3( 6x+5)

Now we will substitute m=6x+5 in our equation as:

(m)^2-10 =-3(m)

m^2-10 =-3m

Upon adding 3m on both sides, we will get:

m^2+3m-10 =-3m+3m

m^2+3m-10 =0

Therefore, the equation m^2+3m-10 =0 is equivalent to (6x + 5)^2-10 =-18x-15 in terms of m.

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Alinara [238K]

The solution is:

3\leq y\leq 10

Or

y ≥ 3 and y≤10

Further explanation:

The given inequality is compound inequality which is solved in two parts.

Given inequality is:

10 \leq 2y+4\leq 24

The two inequalities which will be formed are:

2y+4\geq 10\\2y+4\leq 24

Solving one by one

2y+4\geq 10\\2y+4-4\geq 10-4\\2y\geq 6\\\frac{2y}{2} \geq \frac{6}{2} \\ y \geq 3\\2y+4\leq 24\\2y+4-4\leq 24-4\\2y\leq 20\\\frac{2y}{2}\leq \frac{20}{2} \\y\leq 10

The solution is:

3\leq y\leq 10

Or

y ≥ 3 and y≤10

Keywords: Inequalities, Compound inequalities

Learn more about inequalities at:

  • brainly.com/question/6703816
  • brainly.com/question/10402163

#LearnwithBrainly

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