Question

Y=8(x^2+4)+17+-32 in vertex form

Answer 1

$y = 8( {x}^{2} + 4) + 17 + ( - 32)$
$y = 8( {x}^{2} + 4) + 17 - 32$
$y = 8 {x}^{2} + 32 + 17 - 32$
$y = 8 {x}^{2} + 17$
compare to the formula:
$y = a( {x}^{2} - h) + k$
$y = 8( {x}^{2} - 0) + 17$
a = 8
h = 0
k = 17