Question

M^5-m^7. probably easier for most but having a brain fart​

Answer 1

$\bf m^5-m^7\implies \begin{array}{llll} m^5&(1-m^2)\\\\ &(1^2-m^2)\\\\ &(1-m)(1+m) \end{array} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill m^5(1-m)(1+m)~\hfill$

recall that

1² = 1

1⁴ = 1

1⁸⁹⁹⁹⁹⁹⁹⁹⁹ = 1