Answer:
11200 for 7 engines for a total of 80 hours
Step-by-step explanation:
You have 8 engines burning 12000 .for 10 hours.
Divide 10 hours into 12000=1200 PER hour.
1200 ÷8 engines = 140 per hour per engine.
140 × # of hours (12)=1680 for 12 hours per engine.
# of engines × 1680 for 12 hour/per engine
5×1680 = 8400 of fuel for 12 hours/5 engine
Then you have 2 that runs 10 hours
2 × 140 per hour per engine =280 × 10 =2800 for 2 engines for 10 hours
8400. + 2800= 11200 of fuel for 6 engines
It's 2.5 bc it goes up by 2.5 everytime
I think it would be 4.
8 breaks down to 4(2) and 12 breaks down to 4(3). Let me know if that helps!
Answer:
The domain restriction for (f/g)(x) is x=7
Step-by-step explanation:
we have
so
Remember that
the denominator can not be equal to zero
so
Find the domain restriction
x-7=0
x=7
therefore
The domain is all real numbers except the number 7
(-∞,7)∪(7,∞)
It would be 3:45 because 12:00 + 3:00= 3:00+0:45=3:45 and if u were to add another quarter (15mins) itd be 4:00
