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RoseWind [281]
3 years ago
8

What is 77.2-43.778?what is 2.072 divided by 5.6

Mathematics
1 answer:
Shkiper50 [21]3 years ago
8 0

2.072/5.6= 0.37

77.2- 43.778= 33.422

Hope this helps!

~LENA~


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Find the domain and range of each relation. Then determine if the relation is a function. ​
Vlad [161]

Answer:

There is no fixed domain, meaning it is ongoing

The range is from -1 ≤ x ≤ 3

It is a function

Step-by-step explanation:

Domain refers to the x values. If there was a domain then there would be a dot or a point signalling that there is a fixed domain, however, there are arrows meaning that it will keep going.

The range refers to the y-values. The lowest y-value is -1 and the highest is 3.

It is a function because, when you do the vertical line test, each x-value has its own y-value.

3 0
3 years ago
A women buys 23 pounds of potatoes. She gives 10% of them to a neighbor and 15% of them to her mother. How many pounds dose she
vlabodo [156]

Answer:

= 17.25 pounds (Answer)

Step-by-step explanation:

Potatoes she bought = 23 pounds

Amount she gave outsiders= 10+15=25%

= 23×25/100= 23/4=5.75 pounds

Potatoes left with her= 23 — 5.75

= 17.25 pounds (Answer)

4 0
2 years ago
Read 2 more answers
WILL MARK BR HELP ME PLZ FAST AS POSSIBLE
posledela
<h2>Answer:</h2>

<h2>cos theta= adjacent side/ hypotenuse</h2><h2 /><h2>cos theta= adjacent side/ hypotenusecos 36= x/8</h2><h2 /><h2>cos theta= adjacent side/ hypotenusecos 36= x/8√5+1/4 = x/8</h2><h2 /><h2>cos theta= adjacent side/ hypotenuse </h2>

cos 36= x/8√5+1/4 = x/8

4.7 is the approximate answer

8 0
3 years ago
Find area and perimeter​ show your work
yan [13]

Answer:

A= 16

P=16

Step-by-step explanation:

A=h^bxb/ 2

P= side+base+side

8 0
2 years ago
A sphere of radius r is cut by a plane h units above the equator, where
Anika [276]
Consider the top half of a sphere centered at the origin with radius r, which can be described by the equation

z=\sqrt{r^2-x^2-y^2}

and consider a plane

z=h

with 0. Call the region between the two surfaces R. The volume of R is given by the triple integral

\displaystyle\iiint_R\mathrm dV=\int_{-\sqrt{r^2-h^2}}^{\sqrt{r^2-h^2}}\int_{-\sqrt{r^2-h^2-x^2}}^{\sqrt{r^2-h^2-x^2}}\int_h^{\sqrt{r^2-x^2-y^2}}\mathrm dz\,\mathrm dy\,\mathrm dx

Converting to polar coordinates will help make this computation easier. Set

\begin{cases}x=\rho\cos\theta\sin\varphi\\y=\rho\sin\theta\sin\varphi\\z=\rho\cos\var\phi\end{cases}\implies\mathrm dx\,\mathrm dy\,\mathrm dz=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi

Now, the volume can be computed with the integral

\displaystyle\iiint_R\mathrm dV=\int_0^{2\pi}\int_0^{\arctan\frac{\sqrt{r^2-h^2}}h}\int_{h\sec\varphi}^r\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\varphi\,\mathrm d\theta

You should get

\dfrac{2\pi}3\left(r^3\arctan\dfrac{\sqrt{r^2-h^2}}h-\dfrac{h^3}2\left(\dfrac{r\sqrt{r^2-h^2}}{h^2}+\ln\dfrac{r+\sqrt{r^2-h^2}}h\right)\right)
5 0
3 years ago
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