Find the difference between 900 and 246

The center of a hyperbola is (−4,3) , and one vertex is (−4,7) . The slope of one of the asymptotes is 2.

Monica [59]

Answer:

The answer to your question is below

Step-by-step explanation:

C (-4, 3)

V (-4, 7)

asymptotes = 2 = $\frac{b}{a}$

- This is a vertical hyperbola, the equation is

$\frac{(y - k)^{2} }{a^{2} } + \frac{(x - h)^{2} }{b^{2} } = 1$

slope = 2

a is the distance from the center to the vertex = 4

b = 2(4) = 8

$\frac{(y - 3)^{2} }{4^{2} } + \frac{(x + 4)^{2} }{8^{2} } = 1$

$\frac{(y - 3)^{2} }{16} + \frac{(x + 4)^{2} }{64} = 1$

7 0

3 years ago

Read 2 more answers

Dan has £100. Colin takes £. How much is left

sasho [114]

Answer:

Maybe 99£

Step-by-step explanation:

Please give me brainliest

8 0

2 years ago

Read 2 more answers

Conner and Jana are multiplying (3⁵6⁸)(3⁹6¹⁰).

ad-work [718]

<h3>Conner work is correct. Jana work is wrong</h3>

Solution:

Given that,

Conner and Jana are multiplying:

$(3^56^8)(3^96^{10})$

Given Conner's work is:

$(3^56^8)(3^96^{10}) = 3^{5+9}6^{8+10} = 3^{14}6^{18}$

We have to check if this work is correct

Yes, Conner work is correct

From given,

$(3^56^8)(3^96^{10})\\\\3^5 \times 6^8 \times 3^9 \times 6^{10}$

Use the following law of exponent

$a^m \times a^n = a^{m+n}$

Therefore,

$3^5 \times 6^8 \times 3^9 \times 6^{10} = 3^5 \times 3^9 \times 6^8 \times 6^{10} = 3^{5+9} \times 6^{8+10} = 3^{14} \times 6^{18}$

Given Jana's work is:

$(3^56^8)(3^96^{10}) = 3^{5.9}6^{8.10} = 3^{45}6^{80}$

This is incorrect

The powers of same base has to be added. But here, powers are multiplied which is wrong

7 0

3 years ago

WILL GIVE BRAINLIEST

Eva8 [605]

Answer:

inconsistent

Step-by-step explanation:

The two lines are parallel which means they will never intersect. This means they have no solution. When there is no solution they are inconsistent.

Coincident- same line - infinite solutions

Inconsistent - parallel lines - no solutions

Consistent and independent - 1 solutions

6 0

3 years ago

A map has a scale of 5 in. = 15 mi. If you measured the distance between two cities to be 26 in. On the map, how many miles woul

Reil [10]

Answer:

Actual distance between the two cities given on the map = 78.0 miles

Step-by-step explanation:

Scale used for the actual distance between two cities on a map is,

5 in. = 15 mi.

$\frac{5}{15}$ in. = $\frac{15}{15}$ mi.

1 mi. = $\frac{1}{3}$ in.

1 inch = 3 miles

Therefore, 26 inches on the map = 26 × 3

= 78 miles

Therefore, actual distance between the two cities given on the map = 78.0 miles

5 0

3 years ago