The number of gallons of water in the tank at t=10 is
... W(10) = 160,000 -10(8000 -10) = 80100
The number of gallons of water in the tank at t=10.5 is
... W(10.5) = 160,000 -10.5(8000 -10.5) = 76110.25
The rate of change over the interval is
... (W(10.5) - W(10))/(10.5 - 10) = (76110.25 - 80100)/(0.5) = -7979.5
The average rate of change in the number of gallons of water in the tank over the interval is -7979.5 gal/min.
The sign is negative, so the amount of water is decreasing.
Answer:
B. f(x) = -x + 11
Step-by-step explanation:
First if you rearrange the equation you get f(x) = -x + 11, like this:
x + y = 11
Minus x from both sides
y = -x + 11
F(x) and y are interchangeable so we just put f(x) in
f(x) = -x + 11
Each of the graphs are attached and we see that they are the same!
<em>Hope this helps!!</em>
<em>- Kay</em>
