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3 years ago

The LA theorem is a special case of the

Mathematics

2 answers:

salantis [7]3 years ago

4 0

Answer:

ASA and AAS I think

Step-by-step explanation:

USPshnik [31]3 years ago

4 0

The LA theorem (leg-angle theorem) pertains to right triangles; it can be used to determine if two right triangles are congruent. This theorem is actually just a result or special case of something else pertaining to the congruency of right triangles

Happy to help

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How much is the percent change if the price was $75 and now it is $300?

ale4655 [162]

Answer:

300 percent change

Step-by-step explanation:

300 is 400 percent of 75.(75x4 is 300.) Therefore, the percent change is

400 - 100 = 300.

6 0

3 years ago

explain to a friend Grady wants to buy a basketball video game that cots $59.95 including tax. He has $45.50 in cash and a gift

Tomtit [17]

Well first you would, subtract the gift certificate amount from the video game. Then you would subtract his total cash from the cost of the video game. The equation would look something like this: 45.50 - (59.95 - 15.25). The answer to your problem is yes he would have enough.

3 0

3 years ago

Read 2 more answers

Write an expression for the 12th partial sum of the series 3/2+7/3+19/6+... using summation notation

lapo4ka [179]

Answer:

$S_{12}=\sum_{i=1}^{12} [\frac{3}{2}+(i-1)\times \frac{5}{6}]$

$S_{12}=73$

Step-by-step explanation:

$First\ term\ of\ the\ series(a_1)=\frac{3}{2}\\\\Second\ term\ of\ the\ series(a_2)=\frac{7}{3}\\\\Third\ term\ of\ the\ series(a_3)=\frac{19}{6}\\\\a_2-a_1=\frac{7}{3}-\frac{3}{2}=\frac{5}{6}\\\\a_3-a_2=\frac{19}{6}-\frac{7}{3}=\frac{5}{6}\\\\Hence\ it\ is\ an\ Arithmetic\ Series\ with\ first\ term=\frac{3}{2}\ and\ constant\ difference=\frac{5}{6}$

$a_1=\frac{3}{2}+0\times \frac{5}{6}\\\\a_2=\frac{3}{2}+1\times \frac{5}{6}\\\\a_3=\frac{3}{2}+2\times \frac{5}{6}\\\\.\\.\\.\\a_n=\frac{3}{2}+(n-1)\times \frac{5}{6}\\\\S_n=a_1+a_2+a_3+......+a_n\\\\S_n=(\frac{3}{2}+0\times \frac{5}{6})+(\frac{3}{2}+1\times \frac{5}{6})+(\frac{3}{2}+2\times \frac{5}{6})+....+(\frac{3}{2}+[n-1]\times \frac{5}{6})\\\\S_n=\sum_{i=1}^n [\frac{3}{2}+(i-1)\times \frac{5}{6}]\\\\S_n=(\frac{3}{2}+\frac{3}{2}+\frac{3}{2}+...n\ times)+\frac{5}{6}(1+2+3+4+...+(n-1))\\\\$

$S_n=\frac{3}{2}\times n+\frac{5}{6}\times \frac{n(n-1)}{2}\\\\$

$S_{12}=\sum_{i=1}^{12} [\frac{3}{2}+(i-1)\times \frac{5}{6}]$

$S_{12}=\frac{3}{2}\times 12+\frac{5}{6}\times \frac{(12)(12-1)}{2}\\\\S_{12}=18+55\\\\S_{12}=73$

5 0

3 years ago

Just answer don't waste my time. An art class is making a mural for their school which has a triangle drawn in the middle. The l

OLEGan [10]

Answer:

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Step-by-step explanation:

htjyjwjwk4o47orjluothjfrh5qi6woi623o76woeluhsmgsmfanegruq2yiwyjajgafbrhqtj26iwykw5jqrhrhqqrhq5uq5u14uqtjtqjtqjatiatiatiFUFJfbatabtnafbaFJfutjfjbffbafbafjaafjagjqrhqrjafbf r rhaafjfjafabr atanathbra r r rbbb3rhb qtwhwtjwgjwtjqtjqfb hqtjqfbqfb afbqfhqfhafjwtjukdb sg b th2tj h1rhf b rttt r r rbrbrbrvr rvr r r ecscsgj

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2 years ago

What is the exact value for the expression the square root of 52− the square root of 13 + the square root of 117 ? Simplify if p

avanturin [10]

√52 -√13 +√117

= 2√13 -√13 +3√13

= 4√13 . . . . matches selection A

_____

√52 = √(4·13) = (√4)(√13) = 2√13

√117 = √(9·13) = (√9)(√13) = 3√13

8 0

3 years ago