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Sever21 [200]
2 years ago
8

2-1+5+10+20-5-1-9+9-1+?

Mathematics
2 answers:
hodyreva [135]2 years ago
8 0
<h3>2-1+5+10+20-5-1-9+9-1</h3><h3>=32-3</h3><h3>=29</h3>
konstantin123 [22]2 years ago
8 0

Answer:

15 is the answer sure na sure sa answer sure

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0.242\pm0.0229.

The z-score we need is found by first subtracting the confidence level from 1:
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Divide that by 2:
0.05/2 = 0.025

Subtract that from 1:
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Look this up in the middle of a z-table (http://www.z-table.com) and we see that the z-score is 1.96.

Now our confidence interval is given by
\overline{x} \pm z\times \frac{\sigma}{\sqrt{n}}&#10;\\&#10;\\0.242\pm 1.96 \times (\frac{0.037}{\sqrt{10}})&#10;\\&#10;\\0.242 \pm .0229&#10;\\&#10;\\0.242-0.0229=0.2191&#10;\\&#10;\\0.242+0.0229 = 0.2649
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3 years ago
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6 0
3 years ago
Jim wishes to buy 3 gifts that cost 15 dollars, 9 dollars, and 12 dollars. he has 1/4 of the money he needs, how much more money
Archy [21]
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3 years ago
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5 0
4 years ago
A college-entrance exam is designed so that scores are normally distributed with a mean of 500 and a standard deviation of 100.
Crank

Answer: 1.25

Step-by-step explanation:

Given: A college-entrance exam is designed so that scores are normally distributed with a mean(\mu) = 500 and a standard deviation(\sigma) =  100.

A z-score measures how many standard deviations a given measurement deviates from the mean.

Let Y be a random variable that denotes the scores in the exam.

Formula for z-score = \dfrac{Y-\mu}{\sigma}

Z-score = \dfrac{625-500}{100}

⇒ Z-score = \dfrac{125}{100}

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Therefore , the required z-score = 1.25

6 0
3 years ago
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