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zvonat [6]
3 years ago
15

Janice earns a 4 percent commission for the medical equipment that she sells. If she earned $1,823.94 in commission on the digit

al x-ray machine that she sold, what was the cost of the machine?
Mathematics
2 answers:
RoseWind [281]3 years ago
8 0
$45,598.50

1823.94 x 100 divided by 4
kobusy [5.1K]3 years ago
6 0

Answer:

The cost of the machine was $45,598.50.

Step-by-step explanation:

Janice earns 4% commission for the medical equipment that she sells.

She earned $1,823.94 in commission on the digital x-ray machine that she sold.

Let the value of x-ray machine be x

4% of x = $1,823.94

\frac{4}{100} of x = 1,823.94

x = 1,823.94 ÷ 0.04 = $45,598.50

The cost of the machine was $45,598.50.

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Eric's class consists of 12 males and 16 females. If 3 students are selected at random, find the probability that they
Reptile [31]

Answer:

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

Step-by-step explanation:

Let 'M' be the event of selecting males n(M) = 12

Number of ways of choosing 3 students From all males and females

n(M) = 28C_{3} = \frac{28!}{(28-3)!3!} =\frac{28 X 27 X 26}{3 X 2 X 1 } = 3,276

Number of ways of choosing 3 students From all males

n(M) = 12C_{3} = \frac{12!}{(12-3)!3!} =\frac{12 X 11 X 10}{3 X 2 X 1 } =220

The probability that all are male of choosing '3' students

P(E) = \frac{n(M)}{n(S)} = \frac{12 C_{3} }{28 C_{3} }

P(E) =  \frac{12 C_{3} }{28 C_{3} } = \frac{220}{3276}

P(E) = 0.067 = 6.71%

<u><em>Final answer</em></u>:-

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

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Put in the above

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2 years ago
Read 2 more answers
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