Answer:
<h2>
y = ²/₅
x - 3</h2>
Step-by-step explanation:
Changing to slope-intercept form:
5x + 2y = 12 {subtract 5x from both sides}
2y = -5x + 12 {divide both sides by 2}
y = -⁵/₂
x + 6
y=m₁x+b₁ ⊥ y=m₂x+b₂ ⇔ m₁×m₂ = -1
{Two lines are perpendicular if the product of theirs slopes is equal -1}
y =-⁵/₂
x + 1 ⇒ m₁ = -⁵/₂
-⁵/₂×
m₂ = -1 ⇒ m₂ = ²/₅
So, any line perpendicular to 5x + 2y = 12 must have slope m =²/₅
Answer:
No DB is not a perpendicular bisector of AC
Step-by-step explanation:
This is because as AC is a straight line it's angle degree is 180 which when bisected by DB becomes,
180 ÷ 2 = 90
On both the angles i.e <BDC = <NDA = 90°
To make it a perpendicular bisector but
<BDC is not equal to <NDA is not equal to 90°.
Hence, DB is not a perpendicular bisector of line AC.
The answer to this question is the graph B
I dont know if this helps since no one else is answering I’d like to help
To find slope.. the M in the slope formula of y=Mx+b represents slope
So as long as you know what point on the graph represents what then it should be easy
In most cases.. finding slope is where the line meets on the x axis
