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3 years ago

You can solve equations using____________, which undo each other.

Mathematics

2 answers:

Elena L [17]3 years ago

5 0

You can solve equations using inverse operations, which undo each other.

IgorC [24]3 years ago

3 0

You can solve equations using inverse operations which undo each other.

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Which of the expressions are equivalent to the one below? (14+4)/6

Rufina [12.5K]

Answer:

(A)

Step-by-step explanation:

This sign - / Is the same as this sign - ÷

14+4 = 4+14

This is why (4+14)÷6 = (14+4)/6

Hope this Helps!!! :)

Let me know if this answer was perfect in the comments or if I should change anything! :)

7 0

2 years ago

Read 2 more answers

angie needs to buy 156 candlesbfor a party. each package has 8 candles. how many packages should Angie buy?

andre [41]

20 packages

Step-by-step explanation:

Divide 156 by 8 and you get 19.5. Angie needs 156 candles, so you round 19.5 to 20.

6 0

2 years ago

I need help with Function Operations

Leni [432]

Answer:

490

Step-by-step explanation:

d(x)=700-7(30)

7x 30=210

700-210=490

therefore,

r(x)=490

4 0

2 years ago

Grasshoppers are distributed at random in a large field according to a Poisson process with parameter a 5 2 per square yard. How

HACTEHA [7]

In this question, the Poisson distribution is used.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Parameter of 5.2 per square yard:

This means that $\mu = 5.2r$ , in which r is the radius.

How large should the radius R of a circular sampling region be taken so that the probability of finding at least one in the region equals 0.99?

We want:

$P(X \geq 1) = 1 - P(X = 0) = 0.99$

Thus:

$P(X = 0) = 1 - 0.99 = 0.01$

We have that:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-5.2r}*(5.2r)^{0}}{(0)!} = e^{-5.2r}$

Then

$e^{-5.2r} = 0.01$

$\ln{e^{-5.2r}} = \ln{0.01}$

$-5.2r = \ln{0.01}$

$r = -\frac{\ln{0.01}}{5.2}$

$r = 0.89$

Thus, the radius should be of at least 0.89.

Another example of a Poisson distribution is found at brainly.com/question/24098004

3 0

3 years ago

Pls help will give brainly (again)

Elan Coil [88]

Answer:

Step-by-step explanation:

First, simplify the exponents:

2*(3^6*3*-5)

2*((3*3*3*3*3*3)*(1/3*3*3*3*3))

2*(729*0.00411522633)

Then solve from there:

2*2.99999999457

5.99999998914

Since there is only whole numbers and a fraction present, im assuming you have to round:

5.99999998914

6 is your answer

Hope this helps!

7 0

2 years ago