All categories

3 years ago

Question 1 [5 points]

1 answer:

6 0

If I’m not wrong, it should be 1000-5+9.10% and add it to the tune and divide with the 9.90% and -3 and then you can get your answer

You might be interested in

What makes two quantities proportional

Anuta_ua [19.1K]

Ratio!

Two different numbers are considered proportional if they have the same ratio.
Let’s have an example:
=> I the price of an apple is 2 dollars,
=> then the price of 10 apples are 20 dollar
=> the price of 100 apples are 200 dollars
=> the price of 150 apples are 300 dollars.
And so on…. As long as their values are related, they are proportional.
another example:
=> my hair grows 5 inches in 1 month
=> it grows 10 inches in 2 months

4 0

3 years ago

Read 2 more answers

The position equation for a particle is s of t equals the square root of the quantity t cubed plus 1 where s is measured in feet

vladimir1956 [14]

$\bf s(t)=\sqrt{t^3+1}
\\\\\\
\cfrac{ds}{dt}=\cfrac{1}{2}(t^3+1)^{-\frac{1}{2}}\cdot 3t^2\implies \boxed{\cfrac{ds}{dt}=\cfrac{3t^2}{2\sqrt{t^3+1}}}\leftarrow v(t)
\\\\\\
\cfrac{d^2s}{dt^2}=\cfrac{6t(2\sqrt{t^3+1})-3t^2\left( \frac{3t^2}{\sqrt{t^3+1}} \right)}{(2\sqrt{t^3+1})^2}\implies 
\cfrac{d^2s}{dt^2}=\cfrac{ \frac{6t(2\sqrt{t^3+1})-1}{\sqrt{t^3+1}} }{4(t^3+1)}$

$\bf \cfrac{d^2s}{dt^2}=\cfrac{6t[2(t^3+1)]-1}{4(t^3+1)\sqrt{t^3+1}}\implies 
\boxed{\cfrac{d^2s}{dt^2}=\cfrac{12t^4+12t-1}{4t^3+4\sqrt{t^3+1}}}\leftarrow a(t)\\\\
-------------------------------\\\\a(2)=\cfrac{215~ft^2}{44~sec}$

8 0

3 years ago

Read 2 more answers

Pls help me, I give Brainliest T-T

Bess [88]

Answer:

1. 50

2. 41

3. 14

4. 45

5. 0

6. 20

8 0

3 years ago

Read 2 more answers

NEED HELP ASAPPPPP please

LenaWriter [7]

Answer:

17, -3, -13, -18, -23

Step-by-step explanation:

Plug in the x side into the equation so

g(-4) = -5(-4) -3

g(-4) = 20-3

g(-4) = 17

Therefore that answer is 17

Then you do that for all of them, I don't have the time to do them all but that's the concept for all of them. Hope this helps and hopefully it's not too late. Sorry!

6 0

3 years ago

What are the domain range of f(x)= 1/5 power of x

Snowcat [4.5K]

Answer:

Domain: all real numbers

Range: all real numbers

Step-by-step explanation:

I'm assuming you mean the function $f(x)=x^{\frac{1}{5}}$ . That's usually written

f(x) = x^(1/5) with the ^ meaning "to the power of..." and the fraction exponent in parentheses so as not to be confused with x^1/5 which could mean x to the first power, divided by 5.

Fractional exponents are used to indicate roots. In this case, x is being raised to the 1/5 power, so this is the fifth root of x, written $\sqrt[5]{x}$ . The 5 is called the root index.

For odd roots, like this one, the domain is all real numbers--x can be any number at all. So the domain is all real numbers.

The range is also all real numbers. Attached is a graph of this function. It might not look like it, but the graph rises to the right to any height. The larger x gets, the larger the 5th root gets. A similar thing happens on the left--the smaller x gets, the smaller the 5th root gets.

EDIT: see the comment. For the function $f(x)=(1/5)^x$ , the domain is all real numbers. The range is positive real numbers. I'll attach a graph!

3 0

4 years ago