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BlackZzzverrR [31]
4 years ago
15

When solving a system of equations, Jared found y = x + 10 for one equation and substituted x + 10 for y in the other equation.

Nicole found x = y – 10 for the same equation and substituted y – 10 for x in the other equation. Who is correct? Explain.
Mathematics
2 answers:
Natalka [10]4 years ago
6 0

Answer:

Both Jared and Nicole are correct. You can solve for either variable and use the equivalent expression to create a one-variable equation. Then you can solve. Jared would have created a one-variable equation that can be used to solve for x, whereas Nicole would have created a one-variable equation that can be used to solve for y.

Step-by-step explanation:

meriva4 years ago
4 0
Reading the situation, I can say that Jared and Nicole are correct because they manipulated the equation right. They can either write the equation as y as a function of x then substitute it to the y in the other equation and solve for x. They can also write the equation as x as a function of y and substitute it to x in the other equation and solve for y. For both solution, they will still obtain the same answers.
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The length of a rectangle is 5ft longer than twice the width if the perimeter is 58 ft find the length and width of the rectangl
Travka [436]
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Define x :
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Let the width be x.
Width = x
Length = 2x + 5                // Length is 5ft longer than twice the width

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Formula for Perimeter :
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Perimeter = 2 (Length + Width)

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Find Width :
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58 = 2 ( 2x + 5 + x)         // Substitute Length and Width into formula
58 = 2 (3x + 5)                // Combine like terms
58 = 6x + 10                    // Apply distributive property
48 = 6x                            // Take away 10 from both sides
6x = 48                            // Switch sides. Make x the subject
x = 8                                // Divide by 6 on both sides

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Find Length and Width :
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Width = x = 8 ft
Length = 2x + 5 = 2(8) + 5 = 21 ft

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Answer: The length is 21 ft and the width is 8 ft.
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3 0
3 years ago
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Alexis wanted to understand whether grade level had any relationship to their opinion on extending the school day. She surveyed
MakcuM [25]

Actually there is enough information to solve this problem. First, let us find the total per row and per column.


 (see attached pic)


P(Grade 10 | opposed) with P(opposed | Grade 10)

P(Grade 10 | opposed) = Number in Grade 10 who are opposed / Total number of Opposed (column)

P(Grade 10 | opposed) = 13 / 41 = 0.3171

 

P(opposed | Grade 10) = Number in Grade 10 who are opposed / Total number in Grade 10 (row)

P(opposed | Grade 10) = 13 / 32 = 0.4063

 

Therefore:

P(Grade 10 | opposed) IS NOT EQUAL P(opposed | Grade 10), hence they are dependent events.

 

Answer:

P(Grade 10 | opposed) < P(opposed | Grade 10)

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Volgvan

Answer:

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Step-by-step explanation:

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Using the tangent ratio

tan30° = \frac{opposite}{adjacent} = \frac{30}{x} ( multiply both sides by x )

x × tan30° = 30 ( divide both sides by tan30° )

x = \frac{30}{tan30} ≈ 52.0 m

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Nancy is checking to determine if the expressions x + 4 + x and 6 + 2 x minus 2 are equivalent. When x = 3, she correctly finds
Furkat [3]

Complete question is:

Nancy is checking to determine if the expressions x+4+x and 6+2x-2 are equivalent. When x=3 , she correctly finds that both expressions have a value of 10. When x = 5, she correctly evaluates the first expression to find that x + 4 + x = 14. What about the second expression?

Answer:

when x = 5; both expressions are equivalent and equal to 14

Step-by-step explanation:

We are told the expressions are:

(x + 4 + x) and (6 + 2x - 2).

We are also told that when x = 3,both expressions are equal and have a value of 10 each.

Now, when x = 5; we are told the expression (x + 4 + x) has a value of 14.

So when x = 5,let's find the value of the second expression by putting 5 for x in (6 + 2x - 2);

So, we have; 6 + 2(5) - 2 = 6 + 10 - 2 = 14

So when x = 5; both expressions are equivalent and equal to 14

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4 years ago
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