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3 years ago

If (x,2) and(-2,y) are equal,then find x and y

Mathematics

1 answer:

Zolol [24]3 years ago

7 0

X=-2 and y=2. If they are equal then they are the same thing.

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How do you solve this answer for math -11/8

Alexxandr [17]

Answer:

-1.375

Step-by-step explanation:

7 0

3 years ago

F(3)= 5x^2 - 4x + 9<br> evaluate this quadratic function

Neporo4naja [7]

Answer:

$f(3) = 38$

Step-by-step explanation:

Given the quadratic function

$f\left(x\right)=\:5x^2\:-\:4x\:+\:9$

Evaluating the quadratic function

$f\left(x\right)=\:5x^2\:-\:4x\:+\:9$

substitute x = 3

$f\left(3\right)=\:5\left(3\right)^2\:-\:4\left(4\right)\:+\:9$

$f(3) = 45-16+9$

$f(3) = 38$

Therefore,

$f(3) = 38$

6 0

3 years ago

Look at the picture below to answer the question!! plss

laila [671]

Answer:

x = 15.3°

Step-by-step explanation:

Trig identities:

$sin(x)=\dfrac{O}{H} \ \ \ \ \ cos(x)=\dfrac{A}{H} \ \ \ \ \ tan(x)=\dfrac{O}{A}$

where

x = angle
O = side opposite the angle
A = side adjacent the angle
H = hypotenuse

$sin(46)=\dfrac{11}{x}\\\\\implies x=\dfrac{11}{sin(46)}\\\\\implies x=15.3$

8 0

2 years ago

Determining the input using an equation f (x) = -1/3x + 7

daser333 [38]

Answer:

Step-by-step explanation:

f(x)=2/3

2/3=-1/3x+7

Subtract 7 from both sides

2/3-7=-1/3x

-6 1/3 = -1/3x

Multiply both sides by -3

-3(-6 1/3)=-1/3x(-3)

19 = x

4 0

3 years ago

Given sin(u)= -7/25 and cos(v) = -4/5, what is the exact value of cos(u-v) if both angles are in quadrant 3

solmaris [256]

Given:

$\sin (u)=-\dfrac{7}{25}$

$\cos (v)=-\dfrac{4}{5}$

To find:

The exact value of cos(u-v) if both angles are in quadrant 3.

Solution:

In 3rd quadrant, cos and sin both trigonometric ratios are negative.

We have,

$\sin (u)=-\dfrac{7}{25}$

$\cos (v)=-\dfrac{4}{5}$

Now,

$\cos (u)=-\sqrt{1-\sin^2 (u)}$

$\cos (u)=-\sqrt{1-(-\dfrac{7}{25})^2}$

$\cos (u)=-\sqrt{1-\dfrac{49}{625}}$

$\cos (u)=-\sqrt{\dfrac{625-49}{625}}$

On further simplification, we get

$\cos (u)=-\sqrt{\dfrac{576}{625}}$

$\cos (u)=-\dfrac{24}{25}$

Similarly,

$\sin (v)=-\sqrt{1-\cos^2 (v)}$

$\sin (v)=-\sqrt{1-(-\dfrac{4}{5})^2}$

$\sin (v)=-\sqrt{1-\dfrac{16}{25}}$

$\sin (v)=-\sqrt{\dfrac{25-16}{25}}$

$\sin (v)=-\sqrt{\dfrac{9}{25}}$

$\sin (v)=-\dfrac{3}{5}$

Now,

$\cos (u-v)=\cos u\cos v+\sin u\sin v$

$\cos (u-v)=\left(-\dfrac{24}{25}\right)\left(-\dfrac{4}{5}\right)+\left(-\dfrac{7}{25}\right)\left(-\dfrac{3}{25}\right)$

$\cos (u-v)=\dfrac{96}{625}+\dfrac{21}{625}$

$\cos (u-v)=\dfrac{1 17}{625}$

Therefore, the value of cos (u-v) is 0.1872.

6 0

3 years ago