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MrRa [10]
4 years ago
11

The first barn contained 3 times more hay than the second one. After 20 tons of hay were removed from the first barn and 20 tons

were added to the second barn, the amount of hay in the second barn was 5/7 of the amount remaining in the first barn. How many tons of hay was there in each barn?
Mathematics
1 answer:
pentagon [3]4 years ago
6 0

Answer:

Amount of hay in first barn = 90 tons

Amount of hay in second barn song = 30 tons                

Step-by-step explanation:

Let the amount of hay in second barn be x, then hay in first barn will be 3x.

20 tons of hay was removed from first barn and ws added to second barn.

Now, the amount of hay in first barn = 3x -20

Amount of hay in second barn = x+20

The equation now formed is:

x+20 = \frac{5}{7}(3x-20)

7x+14 = 15x -100

-8x = -240

8x = 240

x = 30

3x = 90

Amount of hay in first barn = 90 tons

Amount of hay in second barn song = 30 tons          



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