Two quadratic functions are shown.
1 answer:
So I think the question is basically asking for the minimum y value you could get from the functions.
For the first function,
to find the minimum y. (Use x=-b/2a to find its vertex)
so in this case a=4 b=8
x=-8/2(4)=-1 the the minimum value will have -1 as its x coordinates,
plug in x=-1 to find y.
(-1,-3) for minimum value for the first function
For the second function,
(-1,0) is the vertex of the function, which is the minimum of the function.
compare the first function with y=-3 and second function y=0.
The first function will have the least minimum value and the coordinates are (-1,-3).
For the first function,
to find the minimum y. (Use x=-b/2a to find its vertex)
so in this case a=4 b=8
x=-8/2(4)=-1 the the minimum value will have -1 as its x coordinates,
(-1,-3) for minimum value for the first function
For the second function,
(-1,0) is the vertex of the function, which is the minimum of the function.
compare the first function with y=-3 and second function y=0.
The first function will have the least minimum value and the coordinates are (-1,-3).
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Then, we are going to do something like factoring, but it's not factoring. An example would be:
If we apply it, we would be left with:
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That's our final answer.
Let me know if you need any more help!
Thanks!
-TetraFish
Then, we are going to do something like factoring, but it's not factoring. An example would be:
If we apply it, we would be left with:
We cancel the common factors, and we are left with:
That's our final answer.
Let me know if you need any more help!
Thanks!
-TetraFish