Quadratic equations are the polynomial equations of degree 2 in one variable of the type $f(x) = ax^{2} + bx + c = 0$ where a, b, c, ∈ R and a ≠ 0.
The standard form of a quadratic equation is $ax^{2} + bx + c = 0$ .

Here, the given equation is $4x^{2}+kx+4=0$

By comparing the given equation with the standard form of the quadratic equation we get,

a = 4

b = k

c = 4

The given quadratic is having one rational solution, which means $b^{2} -4ac=0$

Therefore,

$k^{2} -4 \times 4\times4=0\\k^{2} -64=0\\k^{2} =64\\k=\sqrt{64} \\k=8$

Therefore, the value of k is 8.

Learn more about the quadratic equation is brainly.com/question/8649555

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7 0

1 year ago

Leokris [45]

Answer: y=mx+b

Step-by-step explanation:

7 0

2 years ago

Galina-37 [17]

X * 0.09 + (18000-x)*0.19= 3000
x*(-0.1) + 3420 = 3000
x = -420/(-0.1)
x = 4200

The bank loaned out $4,200 at 9%

4 0

2 years ago