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4 years ago

12

Charlie uses 2 2/3 ounces of garlic to help make a jar of spaghetti sauce. Yesterday, he used 3 1/6 ounces of garlic. How many j

ars of sauce did he make?

1 answer:

fgiga [73]4 years ago

4 0

(2 2/3)/1 = (3 1/6)/x

x = 19/16 = 1 3/16 jars

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A garden has a length of 20 ft. It has a width of 12 ft. What is the area of the garden ?

Crazy boy [7]

Answer:

The answer for your problem is 240

Step-by-step explanation:

A=wl=12·20=240

for this problem all you had to do was multiply

12*20 to get your answer

6 0

3 years ago

Which number is a common multiple of 3 and 4?<br> A) 8<br> B) 14<br> C) 32<br> D) 48

Luba_88 [7]

Answer:

LCM of 3 and 4 is 12

Step-by-step explanation:

This is your answer

6 0

2 years ago

Read 2 more answers

{c(1) = 3/16<br> {c(n)=c(n−1)⋅4<br> <br><br> what is the 3rd term in this sequence?

mote1985 [20]

Answer:

$\large\boxed{c(3)=3}$

Step-by-step explanation:

$\left\{\begin{array}{ccc}c(1)=\dfrac{3}{16}\\\\c(n)=c(n-1)\cdot 4\end{array}\right$

Put n = 2 and next n = 3 to the recursive formula:

$c(2)=c(2-1)\cdot4=c(1)\cdot4\to c(2)=\dfrac{3}{16}\cdot4=\dfrac{3}{4}\\\\c(3)=c(3-1)\cdot4=c(2)\cdot4\to c(3)=\dfrac{3}{4}\cdot4=3$

4 0

3 years ago

Which equation demonstrates the additive identity property?

Bezzdna [24]

Answer:

Step-by-step explanation:

Solve for o in the equation (7 + 4) + (7 - 41) = 14©(7 + 4) + 0 = 7 + 41o(7 + 4)(1) = 7 + 41o(7 + 41) + ( - 7 - 41) = 0

We first need to simplify the expression removing parentheses

Simplify 41o(7 + 4): Distribute the 41o to each term in (7+4)

41o * 7 = (41 * 7)o = 287o 41o * 4 = (41 * 4)o = 164o

Our Total expanded term is 287o + 164o

Simplify 41o(7 + 41): Distribute the 41o to each term in (7+41)

41o * 7 = (41 * 7)o = 287o 41o * 41 = (41 * 41)o = 1681o

Our Total expanded term is 287o + 1681o

Our updated term to work with is (7 + 4) + (7 - 41) = 14©(7 + 4) + 0 = 7 + 287o + 164o(1) = 7 + 287o + 1681o + ( - 7 - 41) = 0

We first need to simplify the expression removing parentheses

Simplify 164o(1): Distribute the 164o to each term in (1)

164o * 1 = (164 * 1)o = 164o Our Total expanded term is 164o

Our updated term to work with is (7 + 4) + (7 - 41) = 14©(7 + 4) + 0 = 7 + 287o + 164o = 7 + 287o + 1681o + ( - 7 - 41) = 0

Step 1: Group variables: We need to group our variables (7 and 14©(7. To do that, we subtract 14©(7 from both sides (7 - 14©(7 = 14©(7 - 14©(7

Step 2: Cancel 14©(7 on the right side: 0o = 0 Step 3: Divide each side of the equation by 0

0o 0 = 0 0 o =

5 0

3 years ago

Read 2 more answers

Using the measurements given below, find the hypotenuse of the triangle.

zloy xaker [14]

Answer:

In the triangle shown, AB = 11, BC = 61. Find AC. Right Triangle ABC v2. 3,600; 3,842; 60; 62. 4. Using the following measurements, find the length of the leg of the right triangle. leg = 5

Step-by-step explanation:

Not sure if that's helpful, but hope it is.

5 0

3 years ago