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polet [3.4K]
3 years ago
8

Solve for x (please show work if possible)

Mathematics
1 answer:
mariarad [96]3 years ago
5 0
X = 5

Solving steps:

1. 2x - 45 = - 35

2. 2x = - 35 + 45

3. 2x = 10

4. x = 5

Hope that helps
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Help with 21 would be much appreciated.
umka2103 [35]

Answer:

\large\boxed{x=2\sqrt{21}\ and\ y=4\sqrt3}

Step-by-step explanation:

Look at the picture.

ΔADC and ΔCDB are similar. Therefore the sides are in proportion:

\dfrac{AD}{CD}=\dfrac{CD}{DB}

We have

AD=14-8=6\\CD=y\\DB=8

Substitute:

\dfrac{6}{y}=\dfrac{y}{8}         <em>cross multiply</em>

y^2=(6)(8)

y^2=48\to y=\sqrt{48}\\\\y=\sqrt{16\cdot3}\\\\y=\sqrt{16}\ cdot\sqrt3\\\\\boxed{y=4\sqrt3}

For x use the Pythagorean theorem:

x^2=6^2+(4\sqrt3)^2\\\\x^2=36+48\\\\x^2=84\to x=\sqrt{84}\\\\x=\sqrt{4\cdot21}\\\\x=\sqrt4\cdot\sqrt{21}\\\\\boxed{x=2\sqrt{21}}

3 0
3 years ago
Find the measure of angle x. A) 90° B) 45° C) 135° D) 180°
tiny-mole [99]
The angles of a triangle always equal 180.

You do 180 - 80 - 45. X = 45.
8 0
3 years ago
3x−8 ≤ 23 OR −4x+26≥6 find x
ElenaW [278]

Answer:

3x-8<=23

3x<=23+8

3x< =31

X< = 10.3

or

-4x+26>=6

-4x>=-20

X>=5

6 0
3 years ago
Can someone help with the polynomials? Please
kolbaska11 [484]

Answer:

22x^2 -10xy + 12x

Step-by-step explanation:

To add and subtract polynomials, combine only like terms. When doing it vertically, stack polynomials and line up the same bases and exponents. Once this is done, simply add and subtract the coefficients.

  10x^2 + 12xy + 4x

+ 12x^2 -22xy + 8x

_________________

22x^2 -10xy + 12x

Here we added 10 + 12 = 22, 12 + -22 = -10 and 4 + 8 = 12.

8 0
3 years ago
help The screen in a theatre is 22 ft high and is positioned 10 ft above the floor, which is flat. The first row of seats is 7 f
Stella [2.4K]
 <span>(a.) 
Let's say α is the angle that subtends from the top of the screen to horizontal eye-level. 
Let β be the angle that subtends from the bottom of the screen to horizontal eye-level. 

tanα = (22 + 10 - 4) / x = 28/x 
α = arctan(28/x) 

tanβ = (10 - 4) / x = 6/x 
β = arctan(6/x) 

Ɵ = α - β 
Ɵ = arctan(28/x) - arctan(6/x) 

(b.) 
tanƟ = tan(α - β) = (tanα - tanβ) / (1 + tanα tanβ) 
tanƟ = (28/x - 6/x) / [1 + (28/x)(6/x)] 
tanƟ = (22/x) / [1 + (168/x²)] 
tanƟ = 22x / (x² + 168) 
Ɵ = arctan[22x / (x² + 168)]</span>
4 0
3 years ago
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