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3 years ago

I need help with this like I need someone to explain it to me

Mathematics

1 answer:

Elina [12.6K]3 years ago

8 0

Answer:

c=5

Step-by-step explanation:

Sorry I did a problem just like this on my paper so im just gonna copy my work

Simplifying

2x + -5 = 2x + -1c

Reorder the terms:

-5 + 2x = 2x + -1c

Reorder the terms:

-5 + 2x = -1c + 2x

Add '-2x' to each side of the equation.

-5 + 2x + -2x = -1c + 2x + -2x

Combine like terms: 2x + -2x = 0

-5 + 0 = -1c + 2x + -2x

-5 = -1c + 2x + -2x

Combine like terms: 2x + -2x = 0

-5 = -1c + 0

-5 = -1c

Solving

-5 = -1c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add 'c' to each side of the equation.

-5 + c = -1c + c

Combine like terms: -1c + c = 0

-5 + c = 0

Add '5' to each side of the equation.

-5 + 5 + c = 0 + 5

Combine like terms: -5 + 5 = 0

0 + c = 0 + 5

c = 0 + 5

Combine like terms: 0 + 5 = 5

c = 5

Simplifying

c = 5

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a) $n=\frac{0.675(1-0.675)}{(\frac{0.02}{1.64})^2}=1475.07$

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And rounded up we have that n=1681

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

If solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by $\alpha=1-0.9=0.1$ and $\alpha/2 =0.05$ . And the critical value would be given by: