3 years ago

Help plz, i will give brainilist award.

Mathematics

2 answers:

nasty-shy [4]3 years ago

8 0

C, order from least to greatest and its whatever is in the middle

tamaranim1 [39]3 years ago

7 0

Use whatever number is in the middle !

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Find the volume generated by revolving about the x-axis the regions bounded by the following graphs: y = sqrt 1+x x = 0 x = 10

Tema [17]

Answer:

60 pi cubic units.

Step-by-step explanation:

Given that a region bounded by

$y = \sqrt{1+x} \\x = 0\\ x = 10$

is revolved around x axis.

To find the volume of generated solid

we know that when a curve is rotated form x=a to x=b around x axis

Volume V = $\int_a^b \pi y^2 dx\\$

Substitute a=0 , b =10 and $y^2 =1+x$

we have

Volume = $\int_0^{10} \pi (1+x) dx\\= \pi (x+\frac{x^2}{2)} \\=\pi(10+50)\\= 60\pi$

Hence volume would be 60 pi cubic units.

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4 years ago

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3 years ago

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The correct answer is x=0

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