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3 years ago

Which could be the name of a point? A. C B. N (calligraphy) C. n D. 1

Mathematics

1 answer:

aalyn [17]3 years ago

8 0

"C" (option A) could be the name of a point

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How many different strings can be made from the letters in MISSISSIPPI, using all the letters

leonid [27]

Hello,

Answer is 11!/(1!*4!*4!*2!)=34650

M: 1
I:4
S:4
P:2

8 0

4 years ago

) Determine the probability that a bit string of length 10 contains exactly 4 or 5 ones.

yanalaym [24]

Answer: 0.4512

Step-by-step explanation:

A bit string is sequence of bits (it only contains 0 and 1).

We assume that the 0 and 1 area equally likely to any place.

i.e. P(0)= P(1)= $\dfrac{1}{2}$

The length of bits : n = 10

Let X = Number of getting ones.

Then , $X \sim Bin(n=10,\ p=\dfrac{1}{2})$

Binomial distribution formula : $P(X=x)=^nC_x p^x q^{n-x}$ , where p= probability of getting success in each event and q= probability of getting failure in each event.

Here , $p=q=\dfrac{1}{2}$

Then ,The probability that a bit string of length 10 contains exactly 4 or 5 ones.

$P(X= 4\ or\ 5)=P(x=4)+P(x=5)\\\\=^{10}C_4(\dfrac{1}{2})^{10}+^{10}C_4(\dfrac{1}{2})^{10}$

$=\dfrac{10!}{4!6!}(\dfrac{1}{2})^{10}+\dfrac{10!}{5!5!}(\dfrac{1}{2})^{10}$

$=(\dfrac{1}{2})^{10}(\dfrac{10!}{4!6!}+\dfrac{10!}{5!5!})$

$=(\dfrac{1}{2})^{10}(210+252)$

$=(0.0009765625)(462)$

$=0.451171875\approx0.4512$

Hence, the probability that a bit string of length 10 contains exactly 4 or 5 ones is 0.4512.

3 0

4 years ago

Sausages come in packets of 12. Bread rolls come in packets of 9. Brian wants to buy enough packs of sausages and rolls so that

likoan [24]

Disheveled shelve should 263

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3 years ago

Tonya’s dog-walking service charges a flat rate of $20 per month, plus $3 per mile that each dog is walked. Beth does not charge

Rzqust [24]

You need to include the question not just the explanation.

5 0

3 years ago

javier has 3 math books that are the same size. he makes a stack by placing the books on top of each other. The total stack is 1

Alexeev081 [22]

Answer:
The height of one book is $\frac{10}{3}$ in

Explanation:
We know that the 3 books are of the same size. This means that the 3 books have the same height.
Assume that each book has a height x in

Now, we know that the total height is 10 in.
Therefore:
x + x + x = 10
3x = 10
x = 10/3 in

Based on the above, the height of one book is 10/3 in

Hope this helps :)

4 0

3 years ago