Let 2x – y = 3 ——— equation 1
Let x + 5y = 14 ——— equation 2
Making x the subject in eqn 1, = x = y + 3 / 2 ——— eqn 3
• Put eqn 3 in eqn 2
(y + 3 / 2) + 5y = 14
6y = 14 – 3/2
6y = 25/2
y = 25/12
• put y = 25/12 in eqn 3
x = (25/12 + 3/2)
x = 43/12
Answer:
Properties in math are used as general rules to solve problems.
I hope this helped!
Step-by-step explanation:
Answer: 14
Step-by-step explanation: just go to the opposite side of the interger and plz Brainlest would be much appreciated.
Answer:
About 14.14
Step-by-step explanation:
V = 4/3pi x r^3
To find the radius, divide the diameter by 2 (1.5)
Substitute 1.5 in place of r and solve the equation.