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GREYUIT [131]
4 years ago
8

Can someone help me out plz ??!

Mathematics
1 answer:
scoray [572]4 years ago
7 0

Answer:

≈ 62.8

Step-by-step explanation:

Using the equal ratios of

\frac{areaof circle}{areaofsector} = \frac{circleangle}{sectorangle}, that is

\frac{100\pi }{sector} = \frac{2\pi }{\frac{2\pi }{5} } = 5, thus

5 × sector = 100π ( divide both sides by 5 )

sector = 20π = 20 × 3.14 = 62.8 units²

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A company plans to enclose three parallel rectangular areas for sorting returned goods. The three areas are within one large rec
Svetlanka [38]

Answer:

The largest total area that can be enclosed will be a square of length 272 yards.

Step-by-step explanation:

First we get the perimeter of the large rectangular enclosure.

Perimeter of a rectangle =2(l + w)

Perimeter of the large rectangular enclosure= 1088 yard

Therefore:

2(L+W)=1088

The region inside the fence is the area

Area: A = LW

We need to solve the perimeter formula for either the length or width.

2L+ 2W= 1088 yd

2W= 1088– 2L

W = \frac{1088-2L}{2}

W = 544–L

Now substitute W = 544–L into the area formula

A = LW

A = L(544 – L)

A = 544L–L²

Since A is a quadratic expression, we re-write the expression with the exponents in descending order.

A = –L²+544L

Next, we look for the value of the x coordinate

L= -\frac{b}{2a}

L= -\frac{544}{2X-1}

L=272 yards

Plugging L=272 yards into the calculation for area:

A = –L²+544L

A(272)=-272²+544(272)

=73984 square yards

Thus the largest area that could be encompassed would be a square where each side has a length of 272 yards and a width of:

W = 544 – L

= 544 – 272

= 272 yards

7 0
3 years ago
HELP! ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
castortr0y [4]

Answer:

(1)1 hour 15 minutes

(2)4:07

(3) 30 minutes

(4) 8:35

Step-by-step explanation:

1.We are given that

Trey and Na'Asia played basketball from 10:30-11:45

We have to find the time  they play basketball.

11:45-10:30

11-10=1 hour

45-30=15 minutes

They played basketball for duration=1 hour 15 minutes

(2)

School left at 3:15

I got home 52 minutes later.

Then, I got home at =3:15+52 minutes

15 minutes+52 minutes=67 minutes

67 minutes=1 hour 7 minutes

Therefore, I got home at 4:07.

(3)

He begins making Macaroni and chees at 6:35

He finished at 7:05.

He cook his food for time =25+5=30 minutes

(4)

Mahkiya and  Madison went to Cheerleading at 7:15

It was over 1 hour and 20 minutes later .

Therefore, time=7:15+1 hour 20 minutes

=(7+1) : (15+20) minutes

=8:35

Hence, it was over at 8:35.

5 0
3 years ago
How do I even work this? Number 8
borishaifa [10]
You do 12 time 2 the 8 times 2 and you can add 15 and 10 and the subtract
3 0
3 years ago
A ball is dropped from a height of 9 m. Each time it strikes the ground it bounces vertically to a height that is 2/3 of the pre
vredina [299]

Answer:

The answer i 9

Step-by-step explanation:

If the ball bounces 2/3 of the height of 9, and a 1/3 of 9 is 3, then 6 is the answer.

6 0
2 years ago
Smiths bakery is baking several large cakes for a community festival. The cakes consist of two geometrically similar shapes as s
Studentka2010 [4]

Answer:

Approximately 313 cakes of similar size as those 50 cut from the smaller cake, can be cut from the bigger cake.

Step-by-step explanation:

The complete question is with the missing image of the cakes is attached to this solution.

From the image provided, the dimensions of the smaller cake = 2 ft × 1.6 ft

The dimensions of the larger cake = 5 ft × 4 ft

50 cakes are obtained from the smaller cake, how many cakes can be obtained from the bigger cake?

Area of the smaller cake = 2 × 1.6 = 3.2 ft²

Area of the bigger cake = 5 × 4 = 20 ft²

3.2 ft² cake provides 50 cakes.

20 ft² cake will provide (20×50/3.2) cakes = 312.5 cakes

Rounded to the nearest piece of cake = 313 cakes

Hope this Helps!!!

6 0
3 years ago
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