Answer:
The largest total area that can be enclosed will be a square of length 272 yards.
Step-by-step explanation:
First we get the perimeter of the large rectangular enclosure.
Perimeter of a rectangle =2(l + w)
Perimeter of the large rectangular enclosure= 1088 yard
Therefore:
2(L+W)=1088
The region inside the fence is the area
Area: A = LW
We need to solve the perimeter formula for either the length or width.
2L+ 2W= 1088 yd
2W= 1088– 2L
W =
W = 544–L
Now substitute W = 544–L into the area formula
A = LW
A = L(544 – L)
A = 544L–L²
Since A is a quadratic expression, we re-write the expression with the exponents in descending order.
A = –L²+544L
Next, we look for the value of the x coordinate
L=272 yards
Plugging L=272 yards into the calculation for area:
A = –L²+544L
A(272)=-272²+544(272)
=73984 square yards
Thus the largest area that could be encompassed would be a square where each side has a length of 272 yards and a width of:
W = 544 – L
= 544 – 272
= 272 yards
Let x represent the horse age
Let y represent the human age
Since the horse age and human age vary directly, we have the relation
Introducing an equality sign, we
Where K is a proportionality constant, evaluated as
Since a 5-year-old horse is equivalent to 15-year old human,
x = 5
y = 15
we have
Thus,
Thus, for a horse who has lived 16 years
x = 16
Answer:
The most appropriate graphical display for this case is the histogram.
Step-by-step explanation:
One of the most used graphical display is <em>the histogram</em>, a term used for the first time by Karl Pearson in 1895.
Suppose the researcher measures different times for a sample of children to "<em>complete a basic reading skills task</em>". The researcher can register any of these different times for each child in the sample and then create different intervals of the same size (in seconds) for all the cases in the sample. Any of these intervals represent a <em>class</em>. For example, we can have a class for 0 to 20 seconds, other for 20 to 40 seconds, and so on.
Well, into any appropriate class, <em>we summarize the number of cases</em> that fall into it, which represents the frequency of them for this class. We can then represent in the x-axis the different intervals of time (classes) and the y-axis the frequency for each class (rectangles of different heights according to the frequency).
In doing so, we can "extract" valuable information from this graph such as (but not limited to):
Thus, for these and other advantages, <em>the histogram</em> is "the most appropriate graphical display for summarizing the frequency of children falling into different intervals of time".
We can show an example of a histogram with hypothetical data regarding this case (see the graph) below). For instance, the most frequent interval is the first (10 - 20) seconds with nine (9) cases, there is probably an outlier between (110 - 120) seconds and the data is not symmetrical (skewed right).
Step-by-step explanation:
the answer is in the picture above
