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IrinaVladis [17]
3 years ago
14

Graph the function f(x) = -x-8x-13

Mathematics
1 answer:
jekas [21]3 years ago
5 0

Answer:

the answer is there...

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Effectus [21]
Given the formula 
V=\frac{4}{3}πR³
so V=\frac{4}{3}π9³=972π
7 0
2 years ago
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The original price of the TV was marked down by $75 to a sale price of $325. What was the original price of the TV
timurjin [86]

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$400

Step-by-step explanation:

Add The two things together

325+75= 400

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Evaluate the definite integral using the graph of f(x)<br> (Image included)
Tanya [424]

a) The first integral corresponds to the area under y = f(x) on the interval [0, 3], which is a right triangle with base 3 and height 5, hence the integral is

\displaystyle \int_0^3 f(x) \, dx = \frac12 \times 3 \times 5 = \boxed{\frac{15}2}

b) The integral is zero since the areas under the curve over [3, 4] and [4, 5] are equal but opposite in sign. In other words, on the interval [3, 5], f(x) is symmetric and odd about x = 4, so

\displaystyle \int_3^5 f(x) \, dx = \int_3^4 f(x) \, dx + \int_4^5 f(x) \, dx = \int_3^4 f(x) \, dx - \int_3^4 f(x) \, dx = \boxed{0}

c) The integral over [5, 9] is the negative of the area of a rectangle with length 9 - 5 = 4 and height 5, so

\displaystyle \int_5^9 f(x) \, dx = -4\times5 = -20

Then by linearity, we have

\displaystyle \int_0^9 f(x) \, dx = \left\{\int_0^3 + \int_3^5 + \int_5^9\right\} f(x) \, dx = \frac{15}2 + 0 - 20 = \boxed{-\frac{25}2}

8 0
2 years ago
Write each number as a product of a decimal number between 1 and 10 and a power of 10.<br> 234,000
MrRa [10]

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2.34 * 10^5.

Step-by-step explanation:

234000 = 2.34 * 10^5

- there are 5 digits after the first number so the exponent is 5.

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3 years ago
The population P of birds in an area is modeled by the exponential model
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(B)Decreasing is the answer
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