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aleksklad [387]
4 years ago
10

B is the midpoint of AC, D is the midpoint of CE, and AE = 9. Find BD.

Mathematics
1 answer:
viva [34]4 years ago
5 0
Answer is on a picture

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Use the commutative or associative property to simplify the expression.<br> 1/3(3y)
yawa3891 [41]

Answer:

y

Step-by-step explanation:

Associative property is when we change the order of the bracket / can solve any order

So 1/3(3y)

= (1/3x 3)y

= 3/3y

= 1y or simply y

8 0
3 years ago
From $25 to $35<br><br><br> The percent increase is
cestrela7 [59]

Answer:

40 percent

Step-by-step explanation:

Start by taking the difference of the two values:

35-25 = 10.

the $10 is how much the value increased by.

To get the percent that the $25 increased by, take 10/25 to get .4

This .4 can then be turned into a percentage when you multiply it by 100. = 40 percent.

You can check your answer by finding 40 percent of 25, which is 10.

4 0
3 years ago
Daniel moves no more than 30 of his sheep and goats into another field. More than 7 of his animals are sheep.Let s represent the
patriot [66]

Answer:

The required inequalities are s+g\leq 30 and s>7.

Step-by-step explanation:

Consider the provided information.

Daniel moves no more than 30 of his sheep and goats into another field.

Let s represent the number of sheep and g represent the number of goats.

No more than means the number of sheep and goats should be less than or equal to 30.

For less than or equal to use the inequality ≤

Hence the required inequality is: s+g\leq 30

More than 7 of his animals are sheep.

This can be represented as:

s>7

Hence, the required inequalities are s+g\leq 30 and s>7.

3 0
3 years ago
How do I calculate - if a car gets 30 miles per gallon, how many miles was the trip?
Elodia [21]

Answer:

Step-by-step explanation:

Divide the number of miles in the trip by the number of miles your vehicle gets per gallon. For example, if you are traveling 1,500 miles to Orlando and your vehicle gets 30 miles per gallon, you will use 50 gallons of fuel.

8 0
4 years ago
Read 2 more answers
Juan and Lizzy are in the final week of their training for a marathon. Juan's goal is to run one mile on the first day of the we
miss Akunina [59]

Answer:

1. Juan's marathon training schedule is an example of a geometric sequence

2. Lizzy's marathon training schedule is an example of an arithmetic sequence

3. Lizzy will be better prepared for the marathon

Step-by-step explanation:

In the arithmetic sequence there is a common difference between each two consecutive terms

In the geometric sequence there is a common ratio between each two consecutive terms

Juan's Schedule

∵ Juan's will run one mile on the first day of the week

∴ a_{1} = 1

∵ He will double the amount he runs each day for the next

   6 days

- That means he multiplies each day by 2 to find how many miles

   he will run next day

∴  a_{2} = 1 × 2 = 2 miles

∴  a_{3} = 2 × 2 = 4 miles

∴  a_{4} = 4 × 2 = 8 miles

∴  a_{5} = 8 × 2 = 16 miles

∴  a_{6} = 16 × 2 = 32 miles

∴  a_{7} = 32 × 2 = 64 miles

That means there is a common ratio 2 between each two consecutive days

1. Juan's marathon training schedule is an example of a geometric sequence

Lizzy's Schedule

∵ Lizzy's will run 10 miles on the first day of the week

∴ a_{1} = 10

∵ She will increase the amount she runs by 3 miles each day for

   the next six days

- That means she adds each day by 3 to find how many miles

    she will run next day

∴  a_{2} = 10 + 3 = 13 miles

∴  a_{3} = 13 + 3 = 16 miles

∴  a_{4} = 16 + 3 = 19 miles

∴  a_{5} = 19 + 3 = 22 miles

∴  a_{6} = 22 + 3 = 25 miles

∴  a_{7} = 25 × 3 = 28 miles

That means there is a common difference 3 between each two consecutive days

2. Lizzy's marathon training schedule is an example of an arithmetic sequence

The rule of the sum of nth term in the geometric sequence is S_{n}=\frac{a_{1}(1-r^{n})}{1-r}

∵ a_{1} = 1 , r = 2 and n = 7

∴  S_{7}=\frac{1(1-2^{7})}{1-2}

∴  S_{7} = 127

∴ Juan will run 127 miles in the final week

The rule of the sum of nth term in the arithmetic sequence is S_{n}=\frac{n}{2}[a_{1}+a_{n}]

∵ n = 7,  a_{1} = 10  and  a_{7} = 28

∴ S_{7}=\frac{7}{2}(10+28)

∴ S_{7} = 133

∴ Lizzy will run 133 miles in the final week

∵ 133 miles > 127 miles

∴ Lizzy will run more miles than Juan

3. Lizzy will be better prepared for the marathon

7 0
3 years ago
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