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3 years ago

Simplify the expression 21z - 6z + 13

Mathematics

2 answers:

valentina_108 [34]3 years ago

4 0

Answer:

15z+13

Step-by-step explanation:

21z-6z+13

Combine like terms (21z+6z) [Because both of these numbers have a Z next to them]

15z+13

Bess [88]3 years ago

3 0

Answer:

15z+13

Step-by-step explanation:

hey! all we have to do is combine like terms.

21z-6z+13

15z+13

there's your answer.

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Help please...Me and geometry are not compatible in any way

ipn [44]

Answer:

It would be the first one honey :)

Step-by-step explanation:

3 0

3 years ago

What is the measurement of the longest line segment in a right rectangular prism that is 26 inches long, 2 inches wide, and 2 in

EastWind [94]

Answer:

$6\sqrt{19} \approx 26.153$ inches.

Step-by-step explanation:

The longest line segment in a right rectangular prism is the diagonal that connects two opposite vertices. On the first diagram attached, the green line segment connecting A and G is one such diagonals. The goal is to find the length of segment $\mathsf{AG}$ .

In this diagram (not to scale,) $\mathsf{AB} = 26$ (length of prism,) $\mathsf{AC} = 2$ (width of prism,) $\mathsf{AE} = 2$ (height of prism.)

Pythagorean Theorem can help find the length of $\mathsf{AG}$ , one of the longest line segments in this prism. However, note that this theorem is intended for right triangles in 2D, not the diagonal in a 3D prism. The workaround is to simply apply this theorem on two different right triangles.

Start by finding the length of line segment $\mathsf{AD}$ . That's the black dotted line in the diagram. In right triangle $\triangle\mathsf{ABD}$ (second diagram,)

Segment $\mathsf{AD}$ is the hypotenuse.
One of the legs of $\triangle\mathsf{ABD}$ is $\mathsf{AB}$ . The length of $\mathsf{AB}$ is $26$ , same as the length of this prism.
Segment $\mathsf{BD}$ is the other leg of this triangle. The length of $\mathsf{BD}$ is $2$ , same as the width of this prism.

Apply the Pythagorean Theorem to right triangle $\triangle\mathsf{ABD}$ to find the length of $\mathsf{AB}$ , the hypotenuse of this triangle:

$\mathsf{AD} = \sqrt{\mathsf{AB}^2 + \mathsf{BD}^2} = \sqrt{26^2 + 2^2}$ .

Consider right triangle $\triangle \mathsf{ADG}$ (third diagram.) In this triangle,

Segment $\mathsf{AG}$ is the hypotenuse, while
$\mathsf{AD}$ and $\mathsf{DG}$ are the two legs.

$\mathsf{AD} = \sqrt{26^2 + 2^2}$ . The length of segment $\mathsf{DG}$ is the same as the height of the rectangular prism, $2$ (inches.) Apply the Pythagorean Theorem to right triangle $\triangle \mathsf{ADG}$ to find the length of the hypotenuse $\mathsf{AG}$ :

$\begin{aligned}\mathsf{AG} &= \sqrt{\mathsf{AD}^2 + \mathsf{GD}^2} \\ &= \sqrt{\left(\sqrt{26^2 + 2^2}\right)^2 + 2^2}\\ &= \sqrt{\left(26^2 + 2^2\right) + 2^2} \\&= 6\sqrt{19} \\&\approx 26.153\end{aligned}$ .

Hence, the length of the longest line segment in this prism is $6\sqrt{19} \approx 26.153$ inches.

5 0

3 years ago

An equestrian club orders magazine subscriptions for new members.

lukranit [14]

Answer: The cost for each subscription is $19.5

Step-by-step explanation:

32m=624

Divide 32 on both sides:

32m/32=624/32

m=19.5

5 0

2 years ago

Read 2 more answers

What do 15/140 equal

Virty [35]

The answer would be 0.10714 or 3/28 if you wanted to simplify it.

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3 years ago

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Consider the statement : Congruent triangles are always similar. Which of the following statements is an example of the statemen

swat32

Answer:

Yes, the congruent triangles are always similar. The following statements are applicable

1) Angles are the same, but sides are proportional to eachother.

2) Sides are the same size.

3)Corresponding angles and corresponding sides are congruent.

Step-by-step explanation:

Yes, they are similar.

For two triangles to be similar, it is sufficient if two angles of one triangle are equal to two angles of the other triangle. Note that if two angles of one are equal to two angles of the other triangle, the third angles of the two triangles too will be equal.

If two triangles are congruent then all corresponding sides as well as corresponding angles of one triangle are equal to those of other triangles. This can happen in four cases

1)- when all sides of triangles are equal,

2) - if one side and two angles of one are equal to one side and two angles of other triangle.

3) - if two sides and included angle of one triangle are equal to two sides and included angle of other triangle

4)- if in two right angled triangles, one side and hypotenuse of one triangle are equal to one side and hypotenuse of other triangle.

Observe that for triangles to be similar, we just need all angles to be equal. But for triangles to be congruent, angles as well as sides should be equal.

Hence, while congruent triangles are similar, similar triangles may not be congruent ( but the converse is not true) .

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3 years ago