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Radda [10]
3 years ago
15

5. Use a table of standard normal curve areas to find the following:

Mathematics
1 answer:
ANTONII [103]3 years ago
7 0

Answer:

a. 0.7123

b. 0.1151

c. 0.0708

d. 0.6368

e. 0.7058

Step-by-step explanation:

  • the area to the right of z* can be stated as P(z<z*), and corresponding probability of z* on z-table gives the result.

a. The area to the left of z = 0.56 = P(z<0.56) = 0.7123

b. The area to the right of z = 1.20 =P(z>1.20)= 1- P(z<1.20)= 1-0,8849=0.1151

c. The area to the left of z = −1.47 = P(z<-1.47)= 0.0708

d. The area to the right of z = −0.35 =P(z>-0.35) = 1-P(z<-0.35)=1-0,3632=0.6368

e. P(-1.39<z<0.80) = P(z<0.80) - P(z<-1.39) = 0.7881-0.0823 = 0.7058

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The shortest whole number height that will hold the fishing pole is 5 feet.

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3 years ago
What type (irrational, Rational, whole, natural, integer) of numbers are these?
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Answer:

See Below

Step-by-step explanation:

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Hope this helps!

5 0
3 years ago
For a certain​ candy, 20​% of the pieces are​ yellow, 15​% are​ red, 20​% are​ blue, 20​% are​ green, and the rest are brown. ​a
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Answer:

Step-by-step explanation:

Based on the question we are given the percentages of each of the types of candies in the bag except for brown. Since the sum of all the percentages equals 75% and brown is the remaining percent then we can calculate that brown is (100-75 = 25%) 25% of the bag. Now we can show the probabilities of getting a certain type of candy by placing the percentages over the total percentage (100%).

  • Brown: \frac{25}{100}
  • Yellow or Blue: \frac{20}{100} +\frac{20}{100} = \frac{40}{100}  ....add the numerators
  • Not Green:  \frac{80}{100}.... since the sum of all the rest is 80%
  • Stiped:  \frac{25}{100} .... there are 0 striped candies.

Assuming the <u><em>ratios/percentages</em></u> of the candies stay the same having an infinite amount of candy will not affect the probabilities. That being said in order to calculate consecutive probability of getting 3 of a certain type in a row we have to multiply the probabilities together. This is calculated by multiplying the numerators with numerators and denominators with denominators.

  • 3 Browns: \frac{25*25*25}{100*100*100} = \frac{15,625}{1,000,000} = \frac{1.5625}{100}

  • the 1st and 3rd are red while the middle is any. We multiply 15% * (total of all minus red which is 85%) * 15% like so.

\frac{15*85*15}{100*100*100} = \frac{19,125}{1,000,000} = \frac{1.9125}{100}

  • None are Yellow: multiply the percent of all minus yellow three times.

\frac{80*80*80}{100*100*100} = \frac{512,000}{1,000,000} = \frac{51.2}{100}

  • At least 1 green: multiply the percent of green by 100% twice, since the other two can by any

\frac{20*100*100}{100*100*100} = \frac{200,000}{1,000,000} = \frac{20}{100}

4 0
3 years ago
Differentiate y= ln l 1+t-t^3 l
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In a flower garden, there are 4 tulips for every 9 daisies. If there are 24 tulips, how many daisies are there? Please help i wi
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54 daisies is the answer


Hope you have a good day!



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