Answer:
An imaginary line would need to be drawn at any angle to the center of the side opposite the angle to reflect across an axis of symmetry so that a regular pentagon can carry onto itself. Hope this answer helps.
There is multiple possibilities:
<span>1050 equals 1 times 1050
1050 equals 2 times 525
1050 equals 3 times 350
1050 equals 5 times 210
1050 equals 6 times 175
1050 equals 7 times 150
1050 equals 10 times 105
1050 equals 14 times 75
1050 equals 15 times 70
1050 equals 21 times 50
1050 equals 25 times 42
1050 equals 30 times 35
1050 equals 35 times 30
1050 equals 42 times 25
1050 equals 50 times 21
1050 equals 70 times 15
1050 equals 75 times 14
1050 equals 105 times 10
1050 equals 150 times 7
1050 equals 175 times 6
1050 equals 210 times 5
1050 equals 350 times 3
1050 equals 525 times 2
1050 equals 1050 times 1</span>
Which Statements?
You didn't put any Statements there
One property of the diagonals of a rhombus is that they are perpendicular bisectors of each other. So 4 congruent right triangles will be formed when you draw the two diagonals. Considering one right triangle, we can solve for the two sides by dividing them by 2.
24 ft/ 2 = 12 ft
18 ft/ 2 = 9 ft
Using the Pythagorean Theorem, we can now solve for the hypotenuse which is the side of the rhombus.
side = √(12²+9²) = 15 ft
The answer is B.
